Question

在以下函数中，我有两个更新语句。第一个执行正常，但第二个则不执行，从而产生错误（无效的参数编号）。阈值是浮点型的（例如，0.55，最多两位），而“可能性”和“后果”是整数。

如何更正我的代码以不产生此错误？

public function updateAll($params = [])
{
    $sql = "update
            risklevels
            set
                riskmaximum = :riskmaximum,
                riskhigh = :riskhigh,
                riskmedium = :riskmedium,
                riskminimum = :riskminimum
            where risklevelid = 1";

    $sql2 = "update
             riskmatrixthresholds
             set 
                level = :level
             where likelihood = :likelhood
             and consequence = :consequence";
    try
    {    
        $this->db->beginTransaction();  
        $statement = $this->db->prepare($sql);
        $statement->bindValue(':riskmaximum', $params['Levels']['riskmaximum']);
        $statement->bindValue(':riskhigh' , $params['Levels']['riskhigh']);
        $statement->bindValue(':riskmedium' , $params['Levels']['riskmedium']);
        $statement->bindValue(':riskminimum' , $params['Levels']['riskminimum']);

        $statement->execute(); 

        for ($l = 1; $l <= 5; $l++)
        {
            for($c = 1; $c <= 5; $c++)
            {
                $threshold = $params['Thresholds'][$l][$c];
                $statement2 = $this->db->prepare($sql2);  
                $statement2->bindValue(':level', $threshold);
                $statement2->bindValue(':likelihood', $l);
                $statement2->bindValue(':consequence', $c);
                $statement2->execute();
            }
        }
        $this->db->commit();

        return ["Succeeded" => true, "Result" => "Risk Configuration Updated!"];
    }
    catch (\PDOException $e)
    {
        return ["Succeeded" => false, "Result" => $e->getMessage()];
    }
}

Answer 1

您拼写了一个SQL变量。

将where likelihood = :likelhood更改为where likelihood = :likelihood

PHP PDO /事务更新状态产生错误（SQLSTATE [HY093]：无效的参数号：未定义参数）

1 个答案: