在我的应用中添加UIAlertController
以显示进度对话框并执行设置后,segue不再执行切换到第二个ViewController
的操作(请参阅问题{{3} }-原来,罪魁祸首不是我最初想的,这就是为什么我要提出一个新问题)。
所以现在我使用Swift 5,Xcode 10和iOS 12设置了一个测试项目,在那里我也遇到了相同的问题:
说明:
onClickLoginButton
UITableView
UIAlertController
,然后应执行到VC2的设置。相反,它仅在控制台中输出一条消息(请参见下面的“控制台输出”)并保持VC1的加载。故事板:
ViewController1:
class ViewController: UIViewController {
@IBOutlet weak var loginButton: UIButton!
var alert:UIAlertController!
var alertMessage:String = ""
override func viewDidLoad() {
super.viewDidLoad()
// Do any additional setup after loading the view.
}
@IBAction func onClickLoginButton(_ sender: Any) {
setUpDialog()
}
private func setUpDialog() {
alertMessage = "Logging in"
alert = UIAlertController(title: "Please wait", message: alertMessage, preferredStyle: UIAlertController.Style.alert)
self.present(alert, animated: true, completion: nil)
performSegue(withIdentifier: "segue12", sender: self)
}
override func prepare(for segue: UIStoryboardSegue, sender: Any?) {
print("prepare 1->2a")
let navVC = segue.destination as? UINavigationController
let tableVC = navVC?.viewControllers.first as! ViewController2
tableVC.test = "Test!"
print("prepare 1->2b")
}
}
ViewController2:
class ViewController2: UIViewController, UITableViewDataSource, UITableViewDelegate {
var test:String = ""
override func viewDidLoad() {
}
func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
return 3
}
func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
let cell = tableView.dequeueReusableCell(withIdentifier: "cell")!
return cell
}
}
控制台输出:
prepare 1->2a
prepare 1->2b
2019-05-21 13:09:16.981738+0200 SegueTest[3505:69382] <UIView: 0x7fc40fd0e790; frame = (0 0; 320 568); autoresize = W+H; layer = <CALayer: 0x600000dc3da0>>'s window is not equal to <UIAlertController: 0x7fc41180ba00>'s view's window!
将此内容添加到prepare
(在print("prepare 1->2b")
之前)会删除对话框,但它仍会输出消息,并且不会切换到第二个视图:
alert.dismiss(animated: true, completion: nil)
以上消息是什么意思(是什么原因引起的?),以及如何修复此测试应用程序,因此它显示对话框,然后切换到ViewController2?
答案 0 :(得分:1)
您无法同时发出警报和进行搜索,请使用DispatchQueue.main.asyncAfter
进行等待
private func setUpDialog() {
alertMessage = "Logging in"
alert = UIAlertController(title: "Please wait", message: alertMessage, preferredStyle: UIAlertController.Style.alert)
self.present(alert, animated: true, completion: nil)
DispatchQueue.main.asyncAfter(deadline: .now() + 2) {
self.alert.dismiss(animated: true, completion: {
self.performSegue(withIdentifier: "segue12", sender: self)
})
}
}