我想创建一个登录表单验证。在那我需要检查用户名和电子邮件是否已经存在。如果存在显示错误
我尝试this tutorial进行CRUD
<?php
defined('BASEPATH') OR exit('No direct script access allowed');
class Insert extends CI_Controller {
// For data insertion
public function index(){
//Setting validation rules
$this->form_validation->set_rules('firstname','First Name','required|alpha');
$this->form_validation->set_rules('lastname','Last Name','required|alpha');
$this->form_validation->set_rules('emailid','Email id','required|valid_email');
$this->form_validation->set_rules('contactno','Contact Number','required|numeric|exact_length[10]');
$this->form_validation->set_rules('address','Address','required');
if($this->form_validation->run()){
$fname=$this->input->post('firstname');
$lname=$this->input->post('lastname');
$email=$this->input->post('emailid');
$cntno=$this->input->post('contactno');
$adrss=$this->input->post('address');
//loading model
$this->load->model('Insert_Model');
$this->Insert_Model->insertdata($fname,$lname,$email,$cntno,$adrss);
$this->load->view('insert');
} else {
$this->load->view('insert');
}
}
}
答案 0 :(得分:3)
您想要做的是如下修改表单验证的规则:
只需将is_unique[tablename.fieldname]
规则添加到表单验证即可。例如:
$this->form_validation->set_rules('emailid','Email id','required|valid_email|is_unique[yourTableName.yourEmailFieldName]');
顺便说一句:您还可以在电子邮件规则中使用修剪
答案 1 :(得分:0)
$this->db->where('emailid', $email); // OTHER CONDITIONS IF ANY
$this->db->from('tblusers'); //TABLE NAME
echo $this->db->count_all_results();
if($this->db->count_all_results() > 0)
{
echo "Duplicate Record";
}
else
{
echo "New record";
}
希望这会帮助您。.只要了解逻辑
答案 2 :(得分:0)
您还可以分配您的自定义验证方法
>> exist eig
ans =
5
>> exist solve
ans =
2
>> exist nosuchfunction
ans =
0
$this->form_validation->set_rules('emailid','Email id','required|valid_email|callback_username_check');