Question

创建一个stringFinding方法，该方法期望一个字符串'x'和另一个字符串'find'作为参数并返回布尔值。如果“搜索”的所有字符以相同的顺序出现，但在“ x”中可能以不同的字母出现，则返回值应为真。

我已经尝试过这段代码，除了一个条件外，所有条件都可以正常工作。


import random, time, os

what = ("Your answer is mine!", "I don't quite know..", "Who knows...")

should = ("Yes, yes you should..", "Don't, please don't", "Okay...")

isvar = ("I believe so.", "No, not at all.....")

amvar = ("Yes, definetly", "No, not at all.....")

whyvar = ("Your answer is mine...", "I dont quite know..")

can = ("Yes, indeed", "No.... Idiot!", "Im not sure..")

question = input("The answer resides within your question, which is..?\n:")

first, *middle, last = question.split()

rwhat = random.choice(what)
rshoud = random.choice(should)
ris = random.choice(isvar)
ram = random.choice(amvar)
rwhy = random.choice(whyvar)
rcan = random.choice(can)

first = str(first)

if (first) == "what" or "What":
    print (rwhat)
    time.sleep(1)
    os.system('pause')

elif (first) == "should" or "Should":
    print (rshoud)
    time.sleep(1)
    os.system('pause')

elif (first) == "is" or "Is":
    print (ris)
    time.sleep(1)
    os.system('pause')

elif (first) == "am" or "Am":
    print (ram)
    time.sleep(1)
    os.system('pause')

elif (first) == "why" or "Why":
    print (rwhy)
    time.sleep(1)
    os.system('pause')

elif (first) == "can" or "Can":
    print (rcan)
    time.sleep(1)
    os.system('pause')

这里是条件

public boolean stringFinden(String x, String suchen){
    String a = "";

    a = x.replaceAll("\\s", "");

    if (a.indexOf(suchen) >= 0 ) {
        return true;
    }
    else { 
        return false;
    }
}

输出应为true（接收为true）

System.out.println (stringFinden ("ab c", "abc"));

输出应为假（接收到假）

System.out.println (stringFinden ("ac b", "abc"));

输出应为true（接收为true）

System.out.println (stringFinden ("xxx", ""));

输出应为假（接收到假）

System.out.println (stringFinden ("1234567", "7521"));

但是在这种情况下，我变得虚假了（输出应该为真）

Answer 1

您需要按顺序检查每个字符，例如：

 public static boolean stringFinden(String x, String suchen){
    int lastCharIndex = -1;
    for (char c : suchen.toCharArray()) {
        int currentCharIndex = x.indexOf(c);
        if (currentCharIndex > lastCharIndex) {
            lastCharIndex = currentCharIndex;
        } else {
            return false;
        }
    }
    return true;
}

任何人都可以在我做错事情的地方帮助我？

1 个答案: