Question

因此下面的Object and Foreach循环恰好完成了我需要做的事情，即找出每行是偶数还是奇数。

$anon = @()
$anon += [PSCustomObject] @{ Name = "i am a thing" ; Location = "1" ; Value = $false }
$anon += [PSCustomObject] @{ Name = "I also do stuff" ; Location = "2" ; Value = $false }
$anon += [PSCustomObject] @{ Name = "I have been known to do stuff" ; Location = "3" ; Value = $true }
$anon += [PSCustomObject] @{ Name = "I do nothing" ; Location = "4" ; Value = $true }

Foreach ( $anonauth in $anon ) {
    If ( $anonauth.location % 2 -eq 0 ) { 
        "I am even, and will do X"   
    }
    Else {
        "I am odd, and will do y"
    }
}

我想知道的是，有没有一种方法可以执行相同的任务而没有“位置”作为IF偶/奇的参考点？

我的对象中有四行，是否可以使用[0]，[1]，[2]，[3]作为计算参考？

这有意义吗？当我确定它已经存在时，拥有参考号似乎是一种浪费？

Answer 1

您可以使用“旧学校” for-loop：

$anon = @()
$anon += [PSCustomObject] @{ Name = "i am a thing" ; Value = $false }
$anon += [PSCustomObject] @{ Name = "I also do stuff" ; Value = $false }
$anon += [PSCustomObject] @{ Name = "I have been known to do stuff" ; Value = $true }
$anon += [PSCustomObject] @{ Name = "I do nothing"; Value = $true }

for( $i =0; $i -lt $anon.Count; $i++ ) {
    If ( $i % 2 -eq 0 ) { 
        "I am even, and will do X"   
    }
    Else {
        "I am odd, and will do y"
    }
}

Answer 2

您可以在foreach循环中实现一些$counter变量，以跟踪到目前为止已迭代的项目数：

$counter = 0
Foreach ( $anonauth in $anon ) {
    $counter += 1 # or, use $counter++
    If ( $counter % 2 -eq 0 ) { 
        "I am even, and will do X"   
    }
    Else {
        "I am odd, and will do y"
    }
}

PSObject的PowerShell索引值

2 个答案: