Question

我在其他具有ID的表中有图像，我想将图像从ID移至其他表。我在变量$ image_url中有逗号分隔的ID，例如1,2。我想将ID为1和2的图像移动到其他表。我该怎么办？

  $image_url = $request->input('image_id');  
  $separate_ids = explode(",", $image_url);

  foreach ($separate_ids as $ids) {

   $result_url['url'] = TempImage::where('id', '=', $separate_ids) 
      ->get(['image']);
            }
                if ($result_url) {

                    $imageModel = new Image();
                    $imageModel->user_id = $userID;
                    $imageModel->user_type = $userType;
                    $imageModel->image = $result_url;
                    $result = $imageModel->save();
                }

Answer 1

您需要重申分离的ID，从存储在每个ID中的表中获取详细信息，然后将其插入目标表中。

foreach($separate_ids as $id) 
{
    // Get the URL according to the image ID
    $url = TempImage::where('id', $id)->first()->image;

    // Store the image
    $imageModel = new Image();
    $imageModel->user_id = $userID;
    $imageModel->user_type = $userType;
    $imageModel->image = $url;
    $imageModel->save();
}

Answer 2

如果json对象中的数据像[{“ id”：1}，{“ id”：2}，{“ id”：3}，{“ id”：4}]

$separate_ids = '[{"id":1},{"id":2},{"id":3},{"id":4}]';

$separate_ids_array = json_decode($separate_ids);

foreach($separate_ids_array as $separate_id) 
{
    // Get the URL according to the image ID
    $url = TempImage::where('id', $separate_id->id)->first()->image;

    // Store the image
    $imageModel = new Image();
    $imageModel->user_id = $userID;
    $imageModel->user_type = $userType;
    $imageModel->image = $url;
    $imageModel->save();
}

如何将数据从一个表移动到另一表？

2 个答案: