按日期过滤，格式为“ dd / mm”

Question

我在语法查询dbms oracle中很难按日期进行过滤，但是我只想按日期（dd / mm）进行过滤。而我的数据数据库记录是（dd / mm / yyyy）。如何查询按日期mm / dd过滤

tablename.fieldname> = '01 / 01'

Answer 1

with s as (
select date '2019-01-01' + level * 15 dt from dual connect by level <= 20)
select s.*
from s
where to_number(to_char(dt, 'mmdd')) > 0501;

DT                 
-------------------
2019-05-16 00:00:00
2019-05-31 00:00:00
2019-06-15 00:00:00
2019-06-30 00:00:00
2019-07-15 00:00:00
2019-07-30 00:00:00
2019-08-14 00:00:00
2019-08-29 00:00:00
2019-09-13 00:00:00
2019-09-28 00:00:00
2019-10-13 00:00:00
2019-10-28 00:00:00

12 rows selected.

Answer 2

您尝试过类似的方法吗？虽然这不是您想要的格式

SELECT * from yourTableName 
WHERE EXTRACT(month from yourDateColumn) >= '1'
AND EXTRACT(day from yourDateColumn) >= '1';

Oracle EXTRACT documentaion

可能的相关问题：

Compare only day and month with date field in mysql

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