我正在尝试打印“图形”程序的深度优先遍历。 DepthFirstTraversal(int v)方法应该从第一个索引开始,该索引应该为A。但是,似乎跳过了这一点。 有什么建议吗?
我尝试将v的值从1更改为0,但这只会在同一代码的顶部额外打印0。
import java.util.Arrays;
import java.util.Iterator;
public class Graph {
private boolean[][] edges;
private int[] labels;
private int N; //number of vertices;
//constructor. This constructor will create a matrix of size n by n.
public Graph(int n) {
N=n;
edges = new boolean[n][n];
labels = new int[n];
}
//this method will allow user to add an edge
public void addEdge(int source, int target) {
edges[source][target] = true;
}
//this method will return the label of the vertex
public int getLabel(int vertex) {
return labels[vertex];
}
//this method will allow user to remove an edge
public void removeEdge(int source, int target) {
edges[source][target] = false;
}
//this method will allow user to set a label
public void setLabels(int vertex, int newLabel) {
labels[vertex] = newLabel;
}
//this method will return the size of the labels array
public int size() {
return labels.length;
}
//this method will grab the neighbors of the desired vertex
public int[] neighbors(int vertex) {
int i;
int counter = 0;
int[] result;
for (i = 0; i < labels.length; i++) {
if (edges[vertex][i])
counter++;
}
result = new int[counter];
counter = 0;
for (i = 0; i < labels.length; i++) {
result[counter++] = i;
}
return result;
}
//this method will print out the vertices starting from the first value
I tried fixing my code a little, but I ran into another problem.
I do have to use neighbors method and also I cannot use recursion.
public void DepthFirstTraversal(int v) {
boolean[] visited = new boolean[N];
Stack<Integer> stack = new Stack<>();
stack.add(v);
visited[v]=true;
while(!stack.isEmpty()){
int i = stack.pop();
if (i == 1) {
System.out.print("A" + "-");
} else if (i == 2) {
System.out.print("B" + "-");
} else if (i == 3) {
System.out.print("C" + "-");
} else if (i == 4) {
System.out.print("D" + "-");
} else if (i == 5) {
System.out.print("E" + "-");
} else if (i == 6) {
System.out.print("F" + "-");
} else if (i == 7) {
System.out.print("G" + "-");
} else if (i == 8) {
System.out.print("H" + "-");
} else if (i == 9) {
System.out.print("I" + "-");
}
System.out.print(labels[i] + " \n");
int[] neighborsOfI = neighbors(i);
for(int k=0;k<neighborsOfI.length;k++){
int neighborTest = neighborsOfI[k];
if(!visited[neighborTest]){
stack.add(neighborTest);
visited[neighborTest]=true;
}
}
}
}
}
public class graphDemo {
public static void main(String args[]){
Graph graph = new Graph(10);
graph.addEdge(1,1);
graph.addEdge(2,3);
graph.addEdge(3,5);
graph.addEdge(4,7);
graph.addEdge(5,9);
graph.addEdge(6,2);
graph.addEdge(7,3);
graph.addEdge(8,5);
graph.addEdge(9,8);
graph.setLabels(1,9);
graph.setLabels(2,3);
graph.setLabels(3,5);
graph.setLabels(4,7);
graph.setLabels(5,4);
graph.setLabels(6,8);
graph.setLabels(7,6);
graph.setLabels(8,2);
graph.setLabels(9,1);
System.out.println("Depth First Traversal from first value: \n");
graph.DepthFirstTraversal(1);
}
}
我期望深度优先遍历从A开始并遵循深度优先遍历直到图形中的最后一个元素,但我却输出以下内容:
从第一个值开始深度遍历:
A-1 I-9
答案 0 :(得分:1)
Java的索引为0,这意味着数组从索引0开始。您正在创建大小为10的数组,但使用后9个条目。我更改了您的输入数据以与此匹配,但这不是问题。
public class GraphDemo {
public static void main(String args[]) {
Graph graph = new Graph(9);
graph.addEdge(0, 0);
graph.addEdge(1, 2);
graph.addEdge(2, 4);
graph.addEdge(3, 6);
graph.addEdge(4, 8);
graph.addEdge(5, 1);
graph.addEdge(6, 2);
graph.addEdge(7, 4);
graph.addEdge(8, 7);
graph.setLabels(0,9);
graph.setLabels(1,3);
graph.setLabels(2,5);
graph.setLabels(3,7);
graph.setLabels(4,4);
graph.setLabels(5,8);
graph.setLabels(6,6);
graph.setLabels(7,2);
graph.setLabels(8,1);
System.out.println("Depth First Traversal from first value: \n");
graph.depthFirstTraversal(1);
}
}
我不确定标签是什么意思,所以我已经完全忽略了它们以及遍历这些标签的邻居。这是两种方法中深度优先遍历的方法:
private void depthFirstTraversal(int v, boolean[] visitedIndexes) {
if (visitedIndexes[v]) {
System.out.println("Arrived at index " + v +
" with letter " + (char) ('A' + v) +
" but we've already been here, so skipping this.");
return;
}
System.out.println("Traversing index " + v +
" which has label " + labels[v] +
" and here's some letter " + (char) ('A' + v)
);
visitedIndexes[v] = true;
for (int i = 0; i < n; i++) {
if (edges[v][i]) {
depthFirstTraversal(i, visitedIndexes);
}
}
}