我在宽大的熊猫数据框中存储了一些长度可变的数字时间序列。每行对应一个系列,每列对应一个测量时间点。由于序列长度不同,这些序列的尾(左)(右)或尾(右)或左(右)可能缺少值(NA)。总是有连续的条纹,每行都没有最小长度的NA。
我需要从这些行的每行中获取固定长度的随机子集,而不包含任何NA。理想情况下,我希望保持原始数据帧完整,并报告新的子集。
我设法以非常低效的for循环(逐行遍历每一行)来确定此输出,确定作物位置的起点,这样NA不会包含在输出中,并复制作物的结果。这可以工作,但是在大型数据集上非常慢。这是代码:
import pandas as pd
import numpy as np
from copy import copy
def crop_random(df_in, output_length, ignore_na_tails=True):
# Initialize new dataframe
colnames = ['X_' + str(i) for i in range(output_length)]
df_crop = pd.DataFrame(index=df_in.index, columns=colnames)
# Go through all rows
for irow in range(df_in.shape[0]):
series = copy(df_in.iloc[irow, :])
series = np.array(series).astype('float')
length = len(series)
if ignore_na_tails:
pos_non_na = np.where(~np.isnan(series))
# Range where the subset might start
lo = pos_non_na[0][0]
hi = pos_non_na[0][-1]
left = np.random.randint(lo, hi - output_length + 2)
else:
left = np.random.randint(0, length - output_length)
series = series[left : left + output_length]
df_crop.iloc[irow, :] = series
return df_crop
还有一个玩具示例:
df = pd.DataFrame.from_dict({'t0': [np.NaN, 1, np.NaN],
't1': [np.NaN, 2, np.NaN],
't2': [np.NaN, 3, np.NaN],
't3': [1, 4, 1],
't4': [2, 5, 2],
't5': [3, 6, 3],
't6': [4, 7, np.NaN],
't7': [5, 8, np.NaN],
't8': [6, 9, np.NaN]})
# t0 t1 t2 t3 t4 t5 t6 t7 t8
# 0 NaN NaN NaN 1 2 3 4 5 6
# 1 1 2 3 4 5 6 7 8 9
# 2 NaN NaN NaN 1 2 3 NaN NaN NaN
crop_random(df, 3)
# One possible output:
# X_0 X_1 X_2
# 0 2 3 4
# 1 7 8 9
# 2 1 2 3
如何以适合大型数据帧的方式获得相同的结果?
编辑:将改进的解决方案移至答案部分。
答案 0 :(得分:1)
我设法通过以下方法大大加快了速度:
def crop_random(dataset, output_length, ignore_na_tails=True):
# Get a random range to crop for each row
def get_range_crop(series, output_length, ignore_na_tails):
series = np.array(series).astype('float')
if ignore_na_tails:
pos_non_na = np.where(~np.isnan(series))
start = pos_non_na[0][0]
end = pos_non_na[0][-1]
left = np.random.randint(start,
end - output_length + 2) # +1 to include last in randint; +1 for slction span
else:
length = len(series)
left = np.random.randint(0, length - output_length)
right = left + output_length
return left, right
# Crop the rows to random range, reset_index to do concat without recreating new columns
range_subset = dataset.apply(get_range_crop, args=(output_length,ignore_na_tails, ), axis = 1)
new_rows = [dataset.iloc[irow, range_subset[irow][0]: range_subset[irow][1]]
for irow in range(dataset.shape[0])]
for row in new_rows:
row.reset_index(drop=True, inplace=True)
# Concatenate all rows
dataset_cropped = pd.concat(new_rows, axis=1).T
return dataset_cropped