Question

我正在尝试使用XML反序列化将XML响应从主机转换为C＃对象。根元素将被转换为其对象，而第二元素将被转换，但无论如何它都是一个空元素。除此之外，没有其他元素被转换。我想念什么？

我为每个元素和元素数组尝试了许多不同的对象变体（即使不需要数组。我什至发现您可以将XML粘贴到Visual Studio的编辑器中，它将创建序列化的对象（编辑，粘贴特殊的XML（作为类粘贴），但是我什么都做不了！

这是XML的外观：

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE paymentService PUBLIC "-//MySite/DTD MySite PaymentService v1//EN" "http://dtd.mysite.com/paymentService_v1.dtd">
<paymentService version="1.4" merchantCode="ExampleCode1">
    <reply>
        <orderStatus orderCode="ExampleOrder1">
            <reference id="YourReference">https://payments-test.mysite.com/app/hpp/integration/wpg/corporate?OrderKey=NGPPTESTMERCH1%5Ejsxml3835829684&amp;Ticket=00146321872957902pqKhCTUf0vajKCw-X5HqZA</reference>
        </orderStatus>
    </reply>
</paymentService>

-或-

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE paymentService PUBLIC "-//MySite//DTD MySite PaymentService v1//EN" "http://dtd.MySite.com/paymentService_v1.dtd">
<paymentService version="1.4" merchantCode="ExampleCode1">
   <reply>
      <orderStatus orderCode="ExampleOrder1">
         <error code="2">
            <![CDATA[Invalid address: Postal code is missing or empty.]]>
        </error>
      </orderStatus>
   </reply>
</paymentService>

这里是对象：

   [Serializable]
   [XmlRoot(ElementName = "paymentService")]
   public partial class PaymentResponse
   {
      [XmlAttribute()]
      public string version { get; set; }

      [XmlAttribute()]
      public string merchantCode { get; set; }

      [XmlElement("reply")]
      public Reply reply { get; set; }
   }
   [Serializable]
   public partial class Reply
   {
      [XmlElement("orderStatus")]
      public OrderStatus orderStatus {get; set; }
   }
   [Serializable]
   public partial class OrderStatus
   {
         [XmlAttribute()]
         public string orderCode {get; set; }

         [XmlElement(ElementName = "reference",IsNullable =true)]
         public Reference reference {get; set; }

         [XmlElement(ElementName = "error",IsNullable =true)]
         public Error error {get; set; }
   }

以下是进行反序列化的电话：

XmlSerializer serializer = new XmlSerializer(typeof(PaymentResponse));
        PaymentResponse response = (PaymentResponse)serializer.Deserialize(reader);

从PaymentResponse返回的商家代码和版本中唯一的内容。

Answer 1

您可能必须告诉序列化程序如何处理非基本类型。

尝试更改此内容

[XmlElement(ElementName = "reference",IsNullable =true)]
public Reference reference {get; set; }

[XmlElement(ElementName = "error",IsNullable =true)]
public Error error {get; set; }

对此

[XmlElement(ElementName = "reference", Type = typeof(Reference), IsNullable = true)]
public Reference reference {get; set; }

[XmlElement(ElementName = "error", Type = typeof(Error), IsNullable = true)]
public Error error {get; set; }

祝你好运！

XML反序列化无法通过第一个元素

1 个答案: