我有一个PHP脚本,用于查询表中每个用户的特定行数。然后,我让SQL查询使用“ AS”在每个用户各自的计数下输出计数;像这样:
<?php
$servername = "localhost";
$username = "name";
$password = "mypassword";
$dbname = "mydatabase";
//Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
//Check connection
if($conn->connect_error) {
die("Connection failed:" . $conn->connect_error);
}
$sql = "SELECT SUM(answer LIKE '%Author: Charlotte Augustine%') AS Charlotte_Posts,SUM(answer LIKE '%Author: Jason Biskie%') AS Biskie_Posts,
SUM(answer LIKE '%Author: Chris Borie%') AS Borie_Posts,
SUM(answer LIKE '%Author: Jason Burton%') AS Burton_Posts,
SUM(answer LIKE '%Author: Marcus Jackman%') AS Jackman_Posts,
SUM(answer LIKE '%Author: Karl Kreder%') AS Kreder_Posts,
SUM(answer LIKE '%Author: Quezada%') AS Quezada_Posts,
SUM(answer LIKE '%Author: Chris Roland%') AS Roland_Posts,
SUM(answer LIKE '%Author: Patrick Shafer%') AS Shafer_Posts,
SUM(answer LIKE '%Author: Patrick Tokeshi%') AS Tokeshi_Posts,
SUM(answer LIKE '%Author: Jonathan Vasquez%') AS Vasquez_Posts
FROM `ost_faq` WHERE created >= curdate() - INTERVAL DAYOFWEEK(curdate())-1 DAY into outfile '/var/lib/mysql-files/posts.txt'";
if (mysqli_query($conn, $sql)) {
echo "Record updated successfully";
} else {
echo "Error updating record: " . mysqli_error($conn);
}
mysqli_close($conn);
?>
现在,如果我在MySQL命令行上运行此查询,则会得到以下输出:
+-----------------+--------------+-------------+--------------+---------------+--------------+---------------+--------------+--------------+---------------+---------------+
| Charlotte_Posts | Biskie_Posts | Borie_Posts | Burton_Posts | Jackman_Posts | Kreder_Posts | Quezada_Posts | Roland_Posts | Shafer_Posts | Tokeshi_Posts | Vasquez_Posts |
+-----------------+--------------+-------------+--------------+---------------+--------------+---------------+--------------+--------------+---------------+---------------+
| 0 | 0 | 0 | 0 | 1 | 0 | 0 | 0 | 0 | 2 | 0 |
+-----------------+--------------+-------------+--------------+---------------+--------------+---------------+--------------+--------------+---------------+---------------+
但是,当我检查输出文件“ posts.txt”时,它所包含的只是数字,就像这样:
0 0 0 0 1 0 0 0 0 2 0
我需要将此数据输出到文本文件,因为然后我将文本文件编入每周发送给自己的自动电子邮件中。
为什么名称不输出到文本文件?我有办法输出“ AS”字符串吗?
我不知道我的自动邮件bash脚本是否引起了问题。如果是这样,请使用以下脚本:
#!/bin/bash
echo "Weekly Stats" > posts.txt
echo "=============================" >> posts.txt
cat "/var/lib/mysql-files/posts.txt" >> posts.txt
if [ -s /var/lib/mysql-files/posts.txt ]
then
cat "posts.txt" | mail -s "Stats" me@domain.com
rm -f /var/lib/mysql-files/posts.txt
else
echo "No Stats Available." | mail -s "No Stats" me@domain.com
rm -f /var/lib/mysql-files/posts.txt
fi
谢谢。
答案 0 :(得分:0)
不幸的是,在outfile
中包含字段名称作为标头的唯一方法是在查询中对标头进行硬编码(请参见此question/answer):
$sql = "
SELECT 'Charlotte_Posts',
'Biskie_Posts' ,
'Borie_Posts' ,
'Burton_Posts' ,
'Jackman_Posts' ,
'Kreder_Posts' ,
'Quezada_Posts' ,
'Roland_Posts' ,
'Shafer_Posts' ,
'Tokeshi_Posts' ,
'Vasquez_Posts'
UNION ALL
SELECT SUM(answer LIKE '%Author: Charlotte Augustine%') AS Charlotte_Posts,
SUM(answer LIKE '%Author: Jason Biskie%') AS Biskie_Posts,
SUM(answer LIKE '%Author: Chris Borie%') AS Borie_Posts,
SUM(answer LIKE '%Author: Jason Burton%') AS Burton_Posts,
SUM(answer LIKE '%Author: Marcus Jackman%') AS Jackman_Posts,
SUM(answer LIKE '%Author: Karl Kreder%') AS Kreder_Posts,
SUM(answer LIKE '%Author: Quezada%') AS Quezada_Posts,
SUM(answer LIKE '%Author: Chris Roland%') AS Roland_Posts,
SUM(answer LIKE '%Author: Patrick Shafer%') AS Shafer_Posts,
SUM(answer LIKE '%Author: Patrick Tokeshi%') AS Tokeshi_Posts,
SUM(answer LIKE '%Author: Jonathan Vasquez%') AS Vasquez_Posts
FROM `ost_faq` WHERE created >= curdate() - INTERVAL DAYOFWEEK(curdate())-1 DAY
INTO OUTFILE '/var/lib/mysql-files/posts.txt'";
在您的上下文中,将MySQL结果从PHP输出到文本文件可能是最简单的方法,而不是由MySQL创建输出文件。 here中提供了一个有关如何根据MySQL查询的数组结果创建此类文件的示例。