Question

数据库查询的输出：

    "_id": "5cd532a8452d22435be6a9ac", 
    "properties": {
        "somerandomname": "asd,
        "someotherrandomname": "adsad"
    }

如何构建这种类型的graphql？

类似的东西：

export const aaa = new GraphQLObjectType({
  name: 'aaa',
  fields: () => ({
    _id: {
      type: GraphQLString
    },
    properties: {
      type: GraphQLObjectType 
    },
  })
});

但是GraphQLObjectType需要配置。

有什么想法吗？

Answer 1

为了实现这一点，您必须定义一个返回GraphQLScalarType的自定义json。您可以在custom-scalars中详细了解它。

或者您可以只使用软件包graphql-type-json，该软件包基本上是返回json的GraphQLScalarType的实现，例如：

const {GraphQLJSON} = require('graphql-type-json');

const aaa = new GraphQLObjectType({
    name: 'aaa',
    fields: () => ({
        _id: {
            type: GraphQLString
        },
        properties: {
            type: GraphQLJSON
        },
    })
});

const RootQuery = new GraphQLObjectType({
    name: 'RootQueryType',
    fields: {
        myField: {
            type: aaa,
            resolve(parent, args) {
                // Here: return your object as it is
                // for example:
                return {
                    _id: "this",
                    properties: {
                        somerandomname: "asd",
                        someotherrandomname: "asdad",
                        "what?!": "it also has strings",
                        noway: [
                            "what about them arrays"
                        ]
                    }
                };
            }
        },
    }
})

然后，如果您查询：

{
  myField {
    _id
    properties
  }
}

您将获得输出：

{
  "data": {
    "myField": {
      "_id": "this",
      "properties": {
        "somerandomname": "asd",
        "someotherrandomname": "asdad",
        "what?!": "it also has strings",
        "noway": [
          "what about them arrays"
        ]
      }
    }
  }
}

具有随机键名的Graphql对象

1 个答案: