Question

我想比较两个字符串并突出显示匹配连续4个或更多单词的单词。

当字符串中有双倍空格或换行时，字符串变亮了，我遇到了问题。

例如假设string1是Lorem ipsum, or lipsum as it is sometimes known, is dummy text used in laying out print, graphic or web designs.

String2是laying out print, graphic

预期输出：

Lorem ipsum, or lipsum as it is sometimes known, is dummy text used in <span style="color:red">laying out print, 

graphic</span> or web designs.

PHP代码：

<?php
$str1 ="Lorem ipsum, or lipsum as it is sometimes known, is dummy text used in laying out print, 
graphic or web designs.";

$str2 = "/laying out print, graphic/iu";

echo preg_replace($str2, '<span style="color:red">$0</span>', $str1);
?>

注意：String1格式应相同。

以下是完整的代码：https://3v4l.org/3pBFR 在此示例中，应突出显示$answer中的最后一段，但不突出显示。

Answer 1

执行此操作的一种方法是将$str2中的任何空白替换为\s+，然后它将匹配$str中的任何空白序列。然后可以在当前操作中将其用于preg_replace：

$str1 ="Lorem ipsum, or lipsum as it is sometimes known, is dummy text used in laying out print, 
graphic or web designs.";

$str2 = "laying   out
print, graphic";

$regex = preg_replace('/\s+/', '\s+', $str2);

echo preg_replace("/$regex/iu", '<span style="color:red">$0</span>', $str1);

输出：

Lorem ipsum, or lipsum as it is sometimes known, is dummy text used in <span style="color:red">laying out print,
graphic</span> or web designs.

Demo on 3v4l.org

比较两个字符串，忽略空格，换行和换行符

1 个答案: