Question

假设我有3个单词：[“ mouse”，“ fish”，“ cat”]

和一个4x3的矩阵

[][][][]
[][][][]
[][][][]

我需要使用2条简单规则将这些单词改组为矩阵：

该单词的连续字母必须垂直或水平相邻
您只能使用一个字母一次（意思是-同一字母不能用于组合2个单词，例如填字游戏）

例如一个很好的组合（使用上面的3个词）：

[C][F][I][M]
[A][H][S][O]
[T][E][S][U]

什么是实现此目标的正确算法？我尝试自己写它，但是以半数有效的算法结束

void Main(){
    string[,] letterGrid = new string[4,3];

    //initialize array
    for (int i = 0; i < letterGrid.GetLength(1); i++)
    {
        for (int t = 0; t < letterGrid.GetLength(0); t++)
        {
            letterGrid[t, i] = "-1";
        }
    }

    string[,] validateGrid = (string[,])letterGrid.Clone();

    string[] words = ["mouse","fish","cat"];       

    Random rnd = new Random();
    //prepare grid
    foreach (string word in words)
    {        
        int rndx = rnd.Next(0, letterGrid.GetLength(0));
        int rndy = rnd.Next(0, letterGrid.GetLength(1));
        letterGrid = GetModifiedGrid((string[,])letterGrid.Clone(), word, rndx, rndy, new List<char> { },            
                     (string[,])validateGrid.Clone(), new int[] { -1, -1});
    }
}


//letterGrid & validate starts as a same matrix consists of -1's
//validate matrix simply marks which cells the function already 'visited'
string[,] GetModifiedGrid(string[,] letterGrid, string word, int x, int y, List<char> chars, string[,] validate, int[] lastPos)
{
    var tempLetterGrid = letterGrid;
    var tempValidate = validate;

    if (chars.Count == word.Length)
    {
        return tempLetterGrid;
    }
    else if(tempValidate[x, y] != word[chars.Count].ToString()) {
        tempValidate[x, y] = word[chars.Count].ToString();
        if (tempLetterGrid[x, y] == "-1" && (lastPos[0] == -1 || ((x == lastPos[0] && Mathf.Abs(y - lastPos[1]) < 2) || (y ==    
        lastPos[1] && Mathf.Abs(x - lastPos[0]) < 2))))
        {
            lastPos[0] = x; lastPos[1] = y;
            tempLetterGrid[x, y] = word[chars.Count].ToString();
            chars.Add(word[chars.Count]);
        }
        if(x + 1 < tempLetterGrid.GetLength(0))
            GetModifiedGrid(tempLetterGrid, word, x + 1, y, chars, tempValidate, lastPos);
        if (y + 1 < tempLetterGrid.GetLength(1))
            GetModifiedGrid(tempLetterGrid, word, x, y + 1, chars, tempValidate, lastPos);
        if (x - 1 >= 0)
            GetModifiedGrid(tempLetterGrid, word, x - 1, y, chars, tempValidate, lastPos);
        if (y - 1 >= 0)
            GetModifiedGrid(tempLetterGrid, word, x, y - 1, chars, tempValidate, lastPos);
    }

    return tempLetterGrid;
}

希望有人能够提供帮助，谢谢。

将给定的单词随机排列到矩阵中

0 个答案: