Question

我正在尝试构建一个自动发送的电子邮件，它将根据包含使用PHPmailer的文件相对路径的变量发送附件。文件路径存储在MYSQL的表中。我想获取使用while循环发送的每封电子邮件的文件路径。有人这样做过吗？电子邮件发送正常但没有附件，并打印出以下错误：

无法访问文件：$ filepath

有问题的代码行是第11,12和27行。感谢您的帮助。

1

 require("PHPMailer_v5.1 2/class.phpmailer.php");
    2    while ($row = mysqli_fetch_array($result)){
    3    $to = $row['email'];
    4    $first_name = $row['first_name'];
    5    $last_name = $row['last_name'];
    6    $msg = $row['msg'];
    7    $id = $row['id'];
    8
    9    //the code in question -lines 11 and 12:
    10
    11   $filepath= $row['filepath'];
    12    $filename= $row['filename'];
    13
    14  $mailer = new PHPMailer();
    15  $mailer->IsSMTP();
    16  $mailer->Host = 'ssl://smtp.gmail.com:465';
    17  $mailer->SMTPAuth = TRUE;
    18  $mailer->Username = 'xx';  // Sender's gmail address
    19  $mailer->Password = 'xx';  // Sender's gmail password
    20  $mailer->From = 'xx';  // Sender's email address
    21  $mailer->FromName = 'xx'; // This is the from name in the email
    22  $mailer->Body = "$msg";
    23  $mailer->Subject = "$id";
    24  $mailer->AddAddress('xx');  // Recipient
    25
    26   //Applying the variables fetched from the database - can this be done?
    27  $mailer->AddAttachment('$filepath', '$filename');
    28  
    29    if(!$mailer->Send())
    30  //more code...

Answer 1

27 $mailer->AddAttachment('$filepath', '$filename');
应该是 27 $mailer->AddAttachment($filepath, $filename);
否则你只需将“$ filepath”和“$ filename”传递给AddAtachment，而不是变量背后的实际数据。

Answer 2

尝试：

$mailer->AddAttachment($filepath, $filename);

使用变量作为邮件附件路径：$ mailer-＆gt; AddAttachment（$ file_variable）;

2 个答案: