给出:
doc1 <- "Hearty Chicken Chorizo, Kale, Bean and Farro Soup"
doc2 <- "Spinach, Ham and Egg Whites Frittata – 2 Points"
doc3 <- "Lentil Tabouli"
doc4 <- "Individual Brussels Sprout & Potato Frittatas"
doc5 <- "Ahi Tuna Stacks with Ginger-Soy Dressing"
doc6 <- "Sagebrush Annie's Ventura County Cabernet Sauvignon & Merlot Ventura County"
doc7 <- "Lentil Chili"
doc8 <- "Slow Cooker Lentil Stew with Sausage"
doc9 <- "Spicy Lentil and Swiss Chard Soup"
doc10 <- "Tofu-Spinach Lasagne"
doc11 <- "Baked Ziti with Spinach"
doc12 <- "Mushroom, Spinach and Cheddar Wraps"
doc13 <- "Jamaican Jerk Pork Roast – Low Carb & Whole 30"
doc14 <- "Skinny Lasagna Rolls"
doc15 <- "Jamaican Jerk Pork Roast – Low Carb & Whole 30"
doc16 <- "Tofu & Broccoli Quinoa Stir-Fry"
doc17 <- "Chicken Fajita Stuffed Peppers"
doc18 <- "SketchBook Pinot Noir Wine"
doc19 <- "Chicken and Vegetable Soup"
doc20 <- "Manhattan Crab Chowder"
doc21 <- "Waterbrook Reserve Chardonnay"
doc22 <- "Chinese Beef and Broccoli"
doc23 <- "Easy Crab Curry"
doc24 <- "Waterbrook Reserve Chardonnay"
我想将它们全部放入R列表:
as.list(c(doc1:doc24))
但是我得到一个错误:
由coercion引入的NA由coercionError引入的NA doc1:doc24:NA / NaN参数
我在这里想念什么?
答案 0 :(得分:1)
要在环境中获取对象,可以将def drawMonsters(monster_start_dict=monsterStart):
[pygame.draw.rect(DISPLAYSURFACE, Blue, (monster_start_dict[m][0], monster_start_dict[m][1], 20, 20)) for m in monster_start_dict.keys()]
与特定的ls
一起使用
pattern
或者您可以使用mget(ls(pattern = "^doc"))
构建它们,然后使用paste0
mget
答案 1 :(得分:1)
我们可以使用mget
使用pattern
来做到这一点,该^
匹配以(doc)后跟一个或多个数字(\\d+
)开头的字符串($
)直到字符串的结尾(mget(ls(pattern = "^doc\\d+$"))
)
{{1}}