Question

在下面的设置中，我有一个简单的输入字段和一个按钮，用户在输入字段中输入一个数字（金额），一旦他们按Submit（提款）按钮，就会出现一个警告对话框（预期）说“您是否要继续$。（来自输入字段的金额）的交易”，那么如果用户单击“确定”，则该金额将传递到php变量，并且数据库交易会发生，如下面的代码所示。问题是首先没有出现警告对话框，因此单击按钮时基本上没有任何反应。

    <?php
     //Actual values hidden
     $dbhost = "xxxxx";
     $dbuser = "rxxxx";
     $dbpass = "xxxxx";
     $db = "xxxxx";

     $conn = new mysqli($dbhost, $dbuser, $dbpass,$db) or die("Connect failed: %s\n". $conn -> error);

       if(! $conn ) {
          echo "Connection failed";
       }
    ?>


    <!DOCTYPE html>
    <!--This is a simple input box to get user input, It has one text box and
    a button-->
    <html>
        <body>
        <form action="doc.php" method="post">
                Enter Amount to Withdraw: <input type="number" name="amount" id="amount" required><br><br>
        <button onClick="myFunction()">Withdraw</button>
        </form>
        </body>
    </html>


    <script>
    //To get user input
    var amount = document.getElementById("amount").value;

    function myFunction() {


      if (confirm("Do you want to proceed with transaction of $."+amount)) {
        <?php 
    //User input (amount) passed to php variable
        $amount = "<script>document.write(amount)</script>";
        $id = "23y4z32";//For specific user

            //To get user row in database
            $getUser = "SELECT * FROM members WHERE id = '$id'";
            $userresult = mysqli_query($conn,$getUser);

            //Result of user row is stored in array $userrow
            $userrow = $userresult->fetch_array(MYSQLI_NUM);

            //To minus users amount user wants to withdraw from his total earning
            $hi1=$userrow[8]-$amount;

            // mysql query to Update transaction data
            $querytransact = "UPDATE members SET bal='$hi1' WHERE id='$id'";
            $resulttransact = mysqli_query($conn,$querytransact);
        ?>   
    //Php ended above
      } else {
    //If user presses "Cancel" on the JS dialogue box
        alert("Transaction cancelled!");
      }
    }
    </script>

如何使用Javascript获取用户输入并将其传递给PHP，最后传递给mysql数据库

0 个答案: