所以我想让Nuxt查询我的GQL API的站点菜单。我是通过nuxtServerInit
存储模块中的index.js
函数来完成此操作的。
像这样:
menuLocations = ["MAIN_MENU", "WORK_MENU"]
store.dispatch("menus/QUERY_MENUS", menuLocations)
从QUERY_MENUS
存储模块中调用我的menus.js
操作。的代码是这样的:
// Define State defaults
export const state = () => ({
locations: {}
})
// Define mutations
export const mutations = {
SET_MENU(state, data) {
//Vue.set(state.locations, data.location, data.items)
//state.locations = { ...state.locations, [data.location]: data.items }
}
}
// Define actions
export const actions = {
async QUERY_MENUS({ commit }, menuLocations) {
let client = this.app.apolloProvider.defaultClient
// Get each menu from server
for (const location of menuLocations) {
const query = await client.query({
query: MenuByLocation,
variables: {
location: location
}
})
// Commit menu to store
commit("SET_MENU", {
location: _camelCase(location),
items: _get(query, "data.menuItems.nodes", {})
})
}
}
}
问题是SET_MENU
中两个注释掉的行都不可靠(未注释时),有时它们行得通,有时却行不通。我猜这与Nuxt和SSR有关,或者我在做异步/等待操作时出错了吗?
此处输入代码沙箱:
代码:https://codesandbox.io/s/j3yjz2wm6y?fontsize=14
预览:https://j3yjz2wm6y.sse.codesandbox.io/
有什么建议吗?谢谢!
答案 0 :(得分:0)
在提供的沙箱中,出现两个错误:
1)nuxtServerInit中没有等待分发的地方
export const actions = {
async nuxtServerInit(store, context) {
let menuLocations = ["MAIN_MENU", "OUR_WORK_MENU"];
await store.dispatch("menus/QUERY_MENUS", menuLocations);
}
};
2)在计算属性中,缺少状态引用
return _get(this, "$store.state.menus.locations.mainMenu", false);
固定的CBS-> https://codesandbox.io/s/rrrv17oq8m