我要将$ id从我的控制器传递给模型,请帮助我
这是我的控制器
class OrderController extends Controller
{
public function show($id,Request $request) {
$data= order_list::select('*')
->where('t_order_list.id_order', $id)
->get();
}
}
如何将$ id传递给我的模型
class order_list extends Model
{
protected $table = "t_order_list";
protected $fillable = ['id_order','id_product','id_variant','qty_order'];
protected $with = ['variant_list'];
public function variant_list($id){
return $this->hasMany('App\Model\variant','id','id_variant')
->join('t_color','t_variant.id_pcolor','=','t_color.id')
->join('t_size','t_variant.id_psize','=','t_size.id')
->join('t_subcategory','t_variant.id_pcategory_sub','=','t_subcategory.id')
->join('t_order_list as d', 't_variant.id', '=', 'd.id_variant')
->select(['t_variant.*','t_color.code_pcolor','t_size.code_psize','t_color.hex_pcolor'
,'t_color.hex_pcolor_2','t_color.hex_pcolor_3',
't_subcategory.name_pcategory_sub','d.qty_order'])
->where('d.id_order', $id);
}
答案 0 :(得分:0)
从Controller调用,如OrderList :: variant_list($ id)并定义函数,如
public static function variant_list($id){
return $this->hasMany('App\Model\variant','id','id_variant')
->join('t_color','t_variant.id_color','=','t_color.id')
->join('t_size','t_variant.id_size','=','t_size.id')
->join('t_subcategory','t_variant.id_subcategory','=','t_subcategory.id')
->join('t_order_list as d', 't_variant.id', '=', 'd.id_variant')
->select(['t_variant.*','t_color.code_color','t_size.code_size','t_color.hex_color'
,'t_color.hex_color_2','t_color.hex_color_3',
't_subcategory.name_subcategory','d.qty_order']);
}
答案 1 :(得分:0)
您可以简单地将变量从控制器传递到模型。
对于普通方法:-
控制器:-UserController
public function test(){
$id = "A";
$user = new User; //create object
$user->passValue($id);
}
型号:-用户
public function passValue($id){
echo $id;
}
对于静态方法:-
public function test(){
$id = "A";
User::passValue($id);
}
型号:-用户
public static function passValue($id){
echo $id;
}