我可以毫无问题地设置模块别名:
"baseUrl": "./app",
"paths": {
"assets/*": ["assets/*"],
"components/*": ["components/*"],
...
},
这有效。但是,我(实际上是我的客户,我想将来将项目的某些部分提取为模块)想要创建子目录作为不同路径的别名(假设所有目录都作为值存在,,并且我不能更改实际的目录结构):
"paths": {
"assets/*": ["assets/*"],
"components/*": ["components/*"],
"@myapp/api/*": ["services/myapp/*"],
"@myapp/state/*": ["state/*"],
},
抛开这是否是一个好的模式/实践(正如我这样要求),在不涉及物理目录结构(并且不使用第三方依赖)的情况下,这在技术上是否可行? (我正在使用Typescript 3.4.3和Vscode 1.33.1)
答案 0 :(得分:0)
"baseUrl": "./",
"paths": {
"@myapp/environment": [ "./src/environments/environment" ],
"@myapp/extensions": [ "./src/extensions" ],
"@myapp/testing": [ "./src/testing" ],
"@myapp/constants": [ "./src/app/shared/constants" ],
"@myapp/data": [ "./src/app/data" ],
"@myapp/shared": [ "./src/app/shared" ],
"@myapp/core/*": [ "./src/app/core/*" ],
"@myapp/*": [ "./src/app/*" ]
}
这就像我项目中的魅力