Question

我有一个正在使用API的函数，并且无需支付JSON

我想要的是仅过滤JSON中的某些特定元素，而不是所有元素我怎样才能做到这一点？

预先感谢您的帮助

function getAllIssueForSCII(){
        var options = {
            method: 'GET',
            url: '***',
            headers: {  
                'Accept': 'application/json',
                'Authorization': "***"
            }
        };

        return new Promise(function (resolve) {
            request(options, function (error, response, data) {
                if (!error && response.statusCode === 200) {
                    console.log('JIRA login success!!')
                    var json = JSON.parse(data);
                    console.log(json); // display all element JSON
                    resolve(json);            
                } else {
                    console.log('error: ' + response.statusCode + ': ' + data.statusMessage)
                }

            })
        })

实际结果：

{
  expand: 'schema,names',
  startAt: 0,
  maxResults: 50,
  total: 2,
  issues: [{
      expand: 'operations,versionedRepresentations,editmeta,changelog,renderedFields',
      id: '59032',
      self: '**',
      key: 'SCII-10',
      fields: [Object]
    },
    {
      expand: 'operations,versionedRepresentations,editmeta,changelog,renderedFields',
      id: '59028',
      self: '**',
      key: 'SCII-7',
      fields: [Object]
    }
  ]
}

预期结果：

{
  issues: [{
        key: 'SCII-10',
        fields: id: 1
        name: toto
        time: now
      },

Answer 1

@Danmoreng在其评论中提到，您只需要浏览JSON。

我想您是javascript新手，让我告诉您：

var jj = { expand: 'schema,names',
startAt: 0,
maxResults: 50,
total: 2,
issues:
[ { expand:
        'operations,versionedRepresentations,editmeta,changelog,renderedFields',
    id: '59032',
    self: '**',
    key: 'SCII-10',
    fields: [Object] },
    { expand:
        'operations,versionedRepresentations,editmeta,changelog,renderedFields',
    id: '59028',
    self: '**',
    key: 'SCII-7',
    fields: [Object] } ] } ;

    var expected_output = {}; // we declare an empty object
    expected_output.issues = []; // we declare "issues" a new field in our object 
    expected_output.issues[0] = {}; // we first element of our array is an object
    expected_output.issues[0].key = jj.issues[0].key; 
    expected_output.issues[0].fields = [];
    expected_output.issues[0].fields = jj.issues[0].fields;
    console.log(expected_output);

Answer 2

应该执行以下操作：

const response = { expand: 'schema,names', startAt: 0, maxResults: 50, total: 2, issues: [ { expand:  'operations,versionedRepresentations,editmeta,changelog,renderedFields', id: '59032', self: '**', key: 'SCII-10', fields: {} }, { expand: 'operations,versionedRepresentations,editmeta,changelog,renderedFields', id: '59028', self: '**', key: 'SCII-7', fields: {} } ] };     

let filterId = '59032';
console.log("Filtered Issues: ", { issues: response.issues.filter(issue => issue.id === filterId ) });

从JSON过滤特定元素

2 个答案: