我试图在编写时计算两个java时间戳之间的分钟差:
时间戳记t1,t2;
t2.getTime()-t1.getTime();
它仅返回两次之间的差,并且
我需要整天(包括几天)的差额
答案 0 :(得分:0)
尝试一下
long difftime = t1.getTime() - t2.getTime();
long seconds = diff / 1000;
long minutes = seconds / 60;
long hours = minutes / 60;
long days = hours / 24;
答案 1 :(得分:0)
假设您的意思是java.sql.Timestamp
,下面的代码似乎可以正常工作:
import java.sql.Timestamp;
class Scratch {
public static final long MINUTES_PER_HOUR = 60;
public static final long SECONDS_PER_MINUTE = 60;
public static final long HOURS_PER_DAY = 24;
public static final long MILLIS_PER_SECOND = 1000L;
public static void main(String[] args) {
long oneDayPlusFiveMinutesInMillis = (MILLIS_PER_SECOND * SECONDS_PER_MINUTE) * ( 5 + MINUTES_PER_HOUR * HOURS_PER_DAY);
Timestamp t0 = new Timestamp(System.currentTimeMillis());
Timestamp t1 = new Timestamp(t0.getTime() + oneDayPlusFiveMinutesInMillis);
long diff = (t1.getTime() - t0.getTime()) / (MILLIS_PER_SECOND * SECONDS_PER_MINUTE);
System.out.println("t1 - t0 = " + diff + " minutes");
}
}
返回:
t1 - t0 = 1445 minutes
答案 2 :(得分:0)
2个时间戳之间的差异给出毫秒。之后应用数学:
// get time difference in seconds
long milliseconds = timestamp2.getTime() - timestamp1.getTime();
int seconds = (int) milliseconds / 1000;
// calculate hours minutes and seconds
int hours = seconds / 3600;
int minutes = (seconds % 3600) / 60;
seconds = (seconds % 3600) % 60;
答案 3 :(得分:0)
Timestamp t1 = new Timestamp(new Date("04/26/2019 20:32:49").getTime());
Timestamp t2 = new Timestamp(new Date("04/27/2019 19:32:49").getTime());
long diff = t2.getTime() - t1.getTime();
long diffSeconds = diff / 1000 % 60;
long diffMinutes = diff / (60 * 1000) % 60;
long diffHours = diff / (60 * 60 * 1000) % 24;
long diffDays = diff / (24 * 60 * 60 * 1000);
long diffTotMinutes = diff / (60 * 1000);
System.out.println("Days: " + diffDays + " \nTime: " + diffHours + ":" + diffMinutes + ":" + diffSeconds);
System.out.println("Total Minutes: " + diffTotMinutes);
输出:
Days: 0
Time: 23:0:0
Total Minutes: 1380