我有一个具有以下值的表:
Type | Value
---------------
A String
A Int
B String
B String
C Double
C Float
,我想知道返回此查询的查询:
Type | String | Int | Double | Float
--------------------------------------------
A 1 1 0 0
B 2 0 0 0
C 0 0 1 1
我该怎么办?
答案 0 :(得分:3)
您可以使用PIVOT
使用以下解决方案:
SELECT Type, [String], [Int], [Double], [Float]
FROM (
SELECT Type, Value
FROM table_name
) st PIVOT (
COUNT(Value)
FOR Value IN ([String], [Int], [Double], [Float])
) AS pt;
如何添加每行的值之和的列和每列的值之和的行?
SELECT Type, [String], [Int], [Double], [Float], TotalRow
FROM (
SELECT Type, Value, COUNT(Value) OVER (PARTITION BY Type) AS TotalRow
FROM test
) st PIVOT (
COUNT(Value)
FOR Value IN ([String], [Int], [Double], [Float])
) pt
UNION ALL
SELECT 'Total', SUM([String]), SUM([Int]), SUM([Double]), SUM([Float]), SUM(TotalRow)
FROM (
SELECT Type, [String], [Int], [Double], [Float], TotalRow
FROM (
SELECT Type, Value, COUNT(Value) OVER (PARTITION BY Type) AS TotalRow
FROM test
) st PIVOT (
COUNT(Value)
FOR Value IN ([String], [Int], [Double], [Float])
) pt
)t;
答案 1 :(得分:2)
您可以尝试使用条件聚合函数。
SELECT Type,
COUNT(CASE WHEN VALUES = 'String' THEN 1 END) 'String',
COUNT(CASE WHEN VALUES = 'Int' THEN 1 END) 'Int',
COUNT(CASE WHEN VALUES = 'Double' THEN 1 END) 'Double',
COUNT(CASE WHEN VALUES = 'Float' THEN 1 END) 'Float'
FROM T
GROUP BY Type
答案 2 :(得分:0)
您还可以使用Dynamic SQL PIVOT
CREATE TABLE test (
DataType VARCHAR(10),
Value VARCHAR(10)
);
INSERT INTO test VALUES
('A', 'String'),
('A', 'Int'),
('B', 'String'),
('B', 'String'),
('C', 'Double'),
('C', 'Float');
DECLARE @cols AS NVARCHAR(MAX),
@query AS NVARCHAR(MAX);
SET @cols = STUFF((SELECT distinct ',' + QUOTENAME(c.Value)
FROM test c
FOR XML PATH(''), Type
).value('.', 'NVARCHAR(MAX)')
,1,1,'')
set @query = 'SELECT DataType, ' + @cols + ' from
(
select DataType,Value
from test
) x
pivot
(
count(Value)
for Value in (' + @cols + ')
) p '
execute(@query)