我正在使用whoosh软件包进行全文模糊匹配。
我当前的代码如下:
from whoosh.index import create_in
from whoosh.fields import *
from whoosh.query import FuzzyTerm
class MyFuzzyTerm(FuzzyTerm):
def __init__(self, fieldname, text, boost=1.0, maxdist=2, prefixlength=1, constantscore=True):
super(MyFuzzyTerm, self).__init__(fieldname, text, boost, maxdist, prefixlength, constantscore)
if not os.path.exists("indexdir"):
os.mkdir("indexdir")
path = u"MMM2.txt"
content = open('MMM2.txt', 'r').read()
schema = Schema(name=TEXT(stored=True), content=TEXT)
ix = create_in("indexdir", schema)
writer = ix.writer()
writer.add_document(name=path, content= content)
writer.commit()
from whoosh.qparser import QueryParser, FuzzyTermPlugin, PhrasePlugin, SequencePlugin
with ix.searcher() as searcher:
parser = QueryParser(u"content", ix.schema,termclass = MyFuzzyTerm)
parser.add_plugin(FuzzyTermPlugin())
parser.remove_plugin_class(PhrasePlugin)
parser.add_plugin(SequencePlugin())
str = u"Tennessee Riverkeeper Inc"
query = parser.parse(str)
# query = parser.parse(u"\"Tennessee Riverkeeper Inc\"~")
results = searcher.search(query)
print ("nb of results =", len(results),results, type(results))
for r in results:
print (r)
在文件MMM2.txt中,它包含以下文本:“ Tennessee aa Riverkeeper aa aa Inc”。理想情况下,我希望程序返回0,因为我想将术语中的单词之间的距离限制在1以内。但是,它仍然返回:
nb of results = 1 <Top 1 Results for And([MyFuzzyTerm('content', 'tennessee', boost=1.000000, maxdist=2, prefixlength=1), MyFuzzyTerm('content', 'riverkeeper', boost=1.000000, maxdist=2, prefixlength=1), MyFuzzyTerm('content', 'inc', boost=1.000000, maxdist=2, prefixlength=1)]) runtime=0.009658594451408662> <class 'whoosh.searching.Results'>
<Hit {'name': 'MMM2.txt'}>
但是,如果我替换:
query = parser.parse(str)
具有:
query = parser.parse(u"\"Tennessee Riverkeeper Inc\"~")
它按我想返回不匹配结果的方式工作。我想这与“〜”有关。但是,当我将字符串替换为变量名时,无法添加它。由于我要匹配的字符串太多,因此无法一一键入。每次循环时,我只能将它们存储到变量中。有什么办法可以解决这个问题?
非常感谢您的提前帮助!
答案 0 :(得分:0)
我知道该怎么做
只是改变:
query = parser.parse('"%s"~' % str)
希望它可以帮助某人!