如何在2次WHERE中选择mysql

Question

我有一张表格，包括PRN，SKP，MUC等。

我想选择带有destionation PRN和SKP的15行，但我不知道怎么做，因为当我写下来

SELECT * FROM destinations WHERE date >= NOW() AND destination = 'PRN' OR 'SKP'

它不会工作它只显示SKP或PRN的地方，我用OR试过这个，并且等等......但是我不能用一种方法工作并选择15个最后目的地，其中destionation = PRN和SKP。 / p>

Answer 1

你可以用作：

SELECT * FROM destinations WHERE date >= NOW() AND (destination = 'PRN' OR destination = 'SKP')

或使用IN运算符

SELECT * FROM destinations WHERE date >= NOW() AND destination IN ('PRN','SKP')

只有15行，您可以在查询后添加“LIMIT 15"

Answer 2

SELECT * FROM destinations WHERE date >= NOW() 
AND (destination = 'PRN' OR destination='SKP')
ORDER BY date desc LIMIT 15

Answer 3

SELECT * FROM destinations WHERE date >= NOW() AND destination IN ('PRN', 'SPK')

或

SELECT * FROM destinations WHERE date >= NOW() AND (destination = 'PRN' OR destination =  'SPK')

应该做的伎俩

Answer 4

使用in通常是最易读的形式（特别是如果你有多个目的地）：

SELECT * FROM destinations WHERE date >= NOW() AND destination IN ( 'PRN' , 'SKP' )

使用或时，请务必在第二个术语周围放置括号，以便首先清除哪个操作符：

SELECT * FROM destinations WHERE date >= NOW() AND (destination = 'PRN' OR destination = 'SPK')

Answer 5

正确的语法是：

SELECT * FROM destinations WHERE date >= NOW() AND (destination = 'PRN' OR destination = 'SKP')

或者：

SELECT * FROM destinations WHERE date >= NOW() AND destination IN ('PRN', 'SKP')

Answer 6

SELECT * FROM destinations WHERE date >= NOW() AND destination IN ('PRN' , 'SKP')