Question

我正在尝试将文件夹中的一组文件从.Xlsx重命名为.xls。到目前为止，这是我所做的：

allFiles = glob.glob("/*.Xlsx") # Folder that has all the files
renamed = []
for filename in allFiles:
    if filename.endswith(".Xlsx"):
        os.rename(filename, filename[:-5])
        renamed.append(filename[:-5]) # removed the .Xlsx extension
        os.path.join(renamed, '.xls') # this fails

我试图查看如何将.xls添加到上述列表renamed

Answer 1

如果我逐行阅读，我认为

这将删除磁盘上文件的所有.xlsx扩展名

os.rename(filename, filename[:-5])         # Problem 1

然后将名称（不带扩展名）添加到列表

renamed.append(filename[:-5])

，然后尝试将a）连接到整个数组上，并将b）连接到文件及其扩展名上，而不是两个路径上

os.path.join(renamed, '.xls')             # Problem 2 and 3

您宁愿

newname = filename[:-5]                  # remove extension
newname = newname + ".xls"               # add new extension
os.rename(filename, newname)             # rename correctly
renamed.append( ... )                    # Whatever name you want in the list

还要注意，对于所有以小写if filename.endswith(".Xlsx"):结尾的文件，False可能是.xlsx。

除了[:-5]，您还可以使用操作系统的帮助：

import glob
import os

allFiles = glob.glob("c:/test/*.xlsx")
renamed = []
for filename in allFiles:
    path, filename = os.path.split(filename)
    basename, extension = os.path.splitext(filename)
    if extension == ".xlsx":
        destination = os.path.join(path, basename+".xls")
        os.rename(filename, destination)

仅供参考：如果重命名是程序的唯一目的，请在Windows命令提示符下尝试ren *.xlsx *.xls。

Answer 2

对于您的全局调用，if filename.endswith(".Xlsx"):应该始终为true。

您混合了您的订单：

os.rename(filename, filename[:-5])  # this renames foo.Xlsx to foo, everything after it is too late.
renamed.append(filename[:-5]) # This adds the file w/o the extension, but also w/o the new extension.
os.path.join(renamed, '.xls') # This is a statement which would produce a result if called correctly (i. e. with a string instead of a list), but the result is discarded.

相反，做

basename = filename[:-5]
newname = os.path.join(basename, '.xls')
os.rename(filename, newname)
renamed.append(basename) # or newname? Choose what you need.

Answer 3

如果我理解正确，那么您目前将流程分为以下几个步骤：

删除xlsx扩展名
将文件添加到列表（无扩展名）
将新扩展名添加到文件中（此失败是因为os.path.join不会将列表作为输入）

为简化起见，我只重命名为新扩展名，如果需要renamed列表，请填充它。像这样：

allFiles = glob.glob("/*.Xlsx") <- Folder that has all the files
renamed = []
for filename in allFiles:
    if filename.endswith(".Xlsx"):
        new_name = filename[:-5]+'.xls'
        os.rename(filename, new_name)
        renamed.append(new_name)

Answer 4

os.path.join不会重命名文件。您应该使用os.rename方法直接将其重命名，

os.rename(filename, filename[:-5]+'.xls')

Python-重命名文件

4 个答案: