Question

我有如下查询

    SELECT DISTINCT table_1.id,
       table_1.time_utc
       table_1.city_uuid,
       cast(table_2.score_rate as decimal(5,3)) as score_rate
FROM integrated_delivery.trip_table_1_fact table_1,
     integrated_product.driver_score_v2 table_2
WHERE table_1.id = table_2.id
  AND table_1.city_uuid = table_2.city_id
  AND table_1.day = date '2019-04-01'
  AND table_2.extract_dt = 20190331
  AND EXISTS
    (SELECT NULL
     FROM table_3
     WHERE table_1.id = table_3.id
       AND table_1.time_utc >= table_3.start_time_utc
       AND table_1.time_utc <= table_3.end_time_utc)

我想更改此查询，使其每隔30分钟返回一次table_1.offer_time_utc。

表_1看起来像样行

       id               time_utc    
b7-19b36a410ab0  2019-04-16 22:00:09.415
53-9127667e288e  2019-04-17 01:06:16.590
6b-a96c3ea196c4  2019-04-16 22:00:09.908

Table_3看起来像

           id          start_time_utc       end_time_utc    
35-e512d080e5d3 2019-01-29 02:00:00.000 2019-01-29 03:30:00.000
94-07e7036c1e4b 2019-01-29 01:30:00.000 2019-01-29 02:30:00.000
7d-20736d277064 2019-01-29 01:00:00.000 2019-01-29 03:30:00.000

我要在哪里调整上面的查询，以便它以30分钟的间隔提取所有记录或行，并且还具有代表该间隔的列？

类似

  interval       
-------------------    
2010-11-16 10:30:00  
2010-11-16 10:35:00
2010-11-16 10:40:00   
2010-11-16 10:45:00
2010-11-16 10:50:00   
2010-11-16 10:55:00

预期的输出基本上将是我在table_1示例中已经拥有的输出，但是间隔如下：

Id               Interval     ( time_utc)
b7-19b36a410ab0  2010-11-16 10:30:00  
53-9127667e288e  2010-11-16 11:00:00
6b-a96c3ea196c4  2010-11-16 11:30:00

谢谢！

Answer 1

TL; DR

以下构造会为任何时间戳生成30分钟的较低边界：

date_trunc('hour', table_1.time_utc) + (
    CASE
        WHEN (extract(minute from table_1.time_utc) >= 30) THEN
            '30 minutes'::interval
        ELSE
            '0'::interval
    END
)

长版

适用于您的情况：

SELECT DISTINCT table_1.id,
       table_1.time_utc,
       date_trunc('hour', table_1.time_utc) + CASE
           WHEN (extract(minute from table_1.time_utc) >= 30) THEN '30 minutes'::interval
           ELSE '0'::interval
       END AS time_utc_aligned,
       table_1.city_uuid,
       cast(table_2.score_rate as decimal(5,3)) as score_rate
FROM integrated_delivery.trip_table_1_fact table_1,
     integrated_product.driver_score_v2 table_2
WHERE table_1.id = table_2.id
      AND table_1.city_uuid = table_2.city_id
      AND table_1.day = date '2019-04-01'
      AND table_2.extract_dt = 20190331
      AND EXISTS (
        SELECT NULL
        FROM table_3
        WHERE table_1.id = table_3.id
              AND table_1.time_utc >= table_3.start_time_utc
              AND table_1.time_utc <= table_3.end_time_utc
      )
;

...会产生（with test data）：

       id        |        time_utc         |  time_utc_aligned   |              city_uuid               | score_rate 
-----------------+-------------------------+---------------------+--------------------------------------+------------
 53-9127667e288e | 2019-04-17 01:06:16.59  | 2019-04-17 01:00:00 | 909153dc-c1ff-4e65-a32e-c9194ddfbec9 |      4.662
 6b-a96c3ea196c4 | 2019-04-16 22:00:09.908 | 2019-04-16 22:00:00 | b2d402a2-ba2d-483b-a4c0-fae95ee1700c |      2.250
 b7-19b36a410ab0 | 2019-04-16 22:00:09.415 | 2019-04-16 22:00:00 | 889f9aed-f399-4059-b97b-d67b0af0096d |      1.744

如果您使用timescale扩展名，则使用其time_bucket C function可以使其更具可读性：

SELECT DISTINCT table_1.id,
       table_1.time_utc,
       time_bucket('30 minutes', table_1.time_utc) AS time_utc_aligned,
       table_1.city_uuid,
       cast(table_2.score_rate as decimal(5,3)) as score_rate
FROM integrated_delivery.trip_table_1_fact table_1,
     integrated_product.driver_score_v2 table_2
WHERE table_1.id = table_2.id
      AND table_1.city_uuid = table_2.city_id
      AND table_1.day = date '2019-04-01'
      AND table_2.extract_dt = 20190331
      AND EXISTS (
        SELECT NULL
        FROM table_3
        WHERE table_1.id = table_3.id
              AND table_1.time_utc >= table_3.start_time_utc
              AND table_1.time_utc <= table_3.end_time_utc
      )
;

Answer 2

我将使用公用表表达式（CTE）并每30分钟创建一个日期时间间隔。您可以在dbfiddle中查看我的示例数据：http://www.sqlfiddle.com/#!4/bf5a7/18

    WITH interval_dates as
    (select  timestamp '2019-04-16 00:00:00' 
                    + NUMTODSINTERVAL(30*rownum-30,'MINUTE')  as from_interval,
     timestamp '2019-04-16 00:00:00' 
                    + NUMTODSINTERVAL(30*rownum,'MINUTE') as to_interval
     from dual connect by level <= 2000)
    select t1.*, dt.from_interval
    from interval_dates dt  
    ,(SELECT DISTINCT table_1.id,
       table_1.time_utc
       table_1.city_uuid,
       cast(table_2.score_rate as decimal(5,3)) as score_rate
FROM integrated_delivery.trip_table_1_fact table_1,
     integrated_product.driver_score_v2 table_2
WHERE table_1.id = table_2.id
  AND table_1.city_uuid = table_2.city_id
  AND table_1.day = date '2019-04-01'
  AND table_2.extract_dt = 20190331
  AND EXISTS
    (SELECT NULL
     FROM table_3
     WHERE table_1.id = table_3.id
       AND table_1.time_utc >= table_3.start_time_utc
       AND table_1.time_utc <= table_3.end_time_utc)) t1
    where t1.time_utc >= dt.from_interval and t1.time_utc < dt.to_interval

抽样结果：

ID              TIME_UTC                FROM_INTERVAL
b7-19b36a410ab0 2019-04-16 22:00:09.0   2019-04-16 22:00:00.0
6b-a96c3ea196c4 2019-04-16 22:00:09.0   2019-04-16 22:00:00.0
53-9127667e288e 2019-04-17 01:06:16.0   2019-04-17 01:00:00.0

SQL-我想每30分钟获取一次查询的时间戳

2 个答案: