Question

我正在尝试编写一个脚本，其中列出了3个变量。

首先，请参阅我当前的脚本：

import datetime as dt
import pandas as pd

x = ['jhon doe', 'GX']

y = ['donald ted', 'GY']

Z = ['smith joe', 'GZ']

start_date = dt.datetime(2019, 4,12)
end_date = dt.datetime(2019, 4,21)
daterange = pd.date_range(start_date, end_date)

for date in daterange:
    print(date)

我为此带来麻烦：

12/04/2019, jhone doe, GX
13/04/2019, donald ted, GY
14/04/2019, smith jhoe, GZ
15/04/2019, jhone doe, GX
16/04/2019, donald ted, GY
17/04/2019, smith jhoe, GZ
18/04/2019, jhone doe, GX
19/04/2019, donald ted, GY
14/04/2019, smith jhoe, GZ
21/04/2019, jhone doe, GX

很明显，如果您看到我的预期输出。

谁能告诉我该怎么做？上面给出了这三个变量。

我认为不需要为此写很多东西

Answer 1

好像您在工具箱中缺少一个工具：from itertools import cycle。

通过cycle，您可以创建一个迭代器，该迭代器可以连续浏览列表。如果您点击列表的末尾，它将返回到开头。

from itertools import cycle

import datetime as dt
import pandas as pd

x = ['jhon doe', 'GX']

y = ['donald ted', 'GY']

z = ['smith joe', 'GZ']
r = (x, y, z)
pool = cycle(r)

start_date = dt.datetime(2019, 4,12)
end_date = dt.datetime(2019, 4,21)
daterange = pd.date_range(start_date, end_date)

for date in daterange:
    curent_person = next(pool)
    print('{}, {}, {}'.format(date.strftime('%d/%m/%Y'), curent_person[0], curent_person[1]))

输出：

12/04/2019, jhon doe, GX
13/04/2019, donald ted, GY
14/04/2019, smith joe, GZ
15/04/2019, jhon doe, GX
16/04/2019, donald ted, GY
17/04/2019, smith joe, GZ
18/04/2019, jhon doe, GX
19/04/2019, donald ted, GY
20/04/2019, smith joe, GZ
21/04/2019, jhon doe, GX

Answer 2

我将使用模函数按一个周期（x，y，Z）打印它。

import datetime as dt
import pandas as pd

x = ['jhon doe', 'GX']

y = ['donald ted', 'GY']

Z = ['smith joe', 'GZ']

start_date = dt.datetime(2019, 4,12)
end_date = dt.datetime(2019, 4,21)
daterange = pd.date_range(start_date, end_date)

i=0
for date in daterange:
    if i % 3 == 0:
        print (date.strftime('%d/%m/%Y'), *x, sep=',')
    elif i % 3 == 1:
        print (date.strftime('%d/%m/%Y'), *y, sep=',')
    else:
        print (date.strftime('%d/%m/%Y'), *Z, sep=',')
    i+=1

结果：

12/04/2019,jhon doe,GX
13/04/2019,donald ted,GY
14/04/2019,smith joe,GZ
15/04/2019,jhon doe,GX
16/04/2019,donald ted,GY
17/04/2019,smith joe,GZ
18/04/2019,jhon doe,GX
19/04/2019,donald ted,GY
20/04/2019,smith joe,GZ
21/04/2019,jhon doe,GX

带有顺序问题的Python Datetime

2 个答案: