Question

我有这种通用方法，用于执行 Post 请求，然后解析这样的响应。

private async Task<object> PostAsync<T1,T2>(string uri, T2 content)
{
    using (var requestMessage = new HttpRequestMessage(HttpMethod.Post, uri))
    {
        var json = JsonConvert.SerializeObject(content);
        using (var stringContent = new StringContent(json, Encoding.UTF8, "application/json"))
        {
            requestMessage.Content = stringContent;

            HttpResponseMessage response = await _client.SendAsync(requestMessage);
            if (response.IsSuccessStatusCode)
            {
                _logger.LogInformation("Request Succeeded");

                T1 responseModel = JsonConvert.DeserializeObject<T1>(await response.Content.ReadAsStringAsync());
                return  responseModel;
            }
            else
            {
                return await GetFailureResponseModel(response);

            }
        }
    }
}

现在的问题是，某些发帖请求响应位于 SnakeCase 中，而其他发于 CamelCase 中。我该如何解决此问题。

Answer 1

鉴于在编译时就知道了snake_case以及需要默认策略时，您可以这样做：

import matplotlib.pyplot as plt
import numpy as np

data = np.random.random(size=100)
f, a = plt.subplots(2, 2, figsize=(10, 5), constrained_layout=True)

a[0,0].plot(data)
a[0,0].set_title("this is a really long title\n"*2)
a[0,1].plot(data)
a[1,1].plot(data)

plt.suptitle("a big long suptitle that runs into the title\n"*2);

因此，当您需要默认策略时：

private Task<object> PostAsync<T1, T2>(string uri, T2 content)
{
    return PostAsync<T1, T2>(uri, content, new DefaultNamingStrategy());
}

private async Task<object> PostAsync<T1, T2>(string uri, T2 content, NamingStragy namingStrategy)
{
    using (var requestMessage = new HttpRequestMessage(HttpMethod.Post, uri))
    {
        var json = JsonConvert.SerializeObject(content);
        using (var stringContent = new StringContent(json, Encoding.UTF8, "application/json"))
        {
            requestMessage.Content = stringContent;

            HttpResponseMessage response = await _client.SendAsync(requestMessage);
            if (response.IsSuccessStatusCode)
            {
                _logger.LogInformation("Request Succeeded");

                var deserializerSettings = new JsonSerializerSettings
                {
                    ContractResolver = new DefaultContractResolver
                    {
                        NamingStrategy = namingStrategy
                    }
                };

                T1 responseModel = JsonConvert.DeserializeObject<T1>(await response.Content.ReadAsStringAsync(), deserializerSettings);
                return responseModel;
            }
            else
            {
                return await GetFailureResponseModel(response);

            }
        }
    }
}

，并且，当您需要snake_case时：

await PostAsync<Some1, Some2>(uri, some2Content);

通用方法Json解析

1 个答案: