Question

我正在使用打字稿和尖角笔。

我有2个非常相似的服务，但是属性不同：

  synchronizedMaps: Map<string, Map<string, MapSynchSettings>> = new Map<string, Map<string, MapSynchSettings>>();
  groupDispatchers: Map<string, Subject<SynchMapGroupSubject>> = new Map<string, Subject<SynchMapGroupSubject>> ();
  mapDispatchers: Map<string, Subject<SynchMapSubject>> = new Map<string, Subject<SynchMapSubject>> ();

  public createNewSynchGroup(id?: string): Observable<SynchMapGroupSubject> {

    this.synchronizedMaps.set(id, new Map<string, MapSynchSettings>());
    this.groupDispatchers.set(id, new Subject<SynchMapGroupSubject>());
    this.mapDispatchers.set(id, new Subject<SynchMapSubject>());

    return this.groupDispatchers.get(id).asObservable();
}

和

  synchronizedDrawer: Map<string, Map<string, SynchWaypointDrawerSettings>> = new Map<string, Map<string, SynchWaypointDrawerSettings>>();
  groupDispatchers: Map<string, Subject<SynchWaypointDrawerGroupSubject>> = new Map<string, Subject<SynchWaypointDrawerGroupSubject>> ();
  waypointDispatchers: Map<string, Subject<SynchWaypointSubject>> = new Map<string, Subject<SynchWaypointSubject>> ();

  constructor() { }

  public createNewSynchGroup(id?: string): Observable<SynchWaypointDrawerGroupSubject> {
    this.synchronizedDrawer.set(id, new Map<string, SynchWaypointDrawerSettings>());
    this.groupDispatchers.set(id, new Subject<SynchWaypointDrawerGroupSubject>());
    this.waypointDispatchers.set(id, new Subject<SynchWaypointSubject>());

    return this.groupDispatchers.get(id).asObservable();
}

属性类型和方法的返回值都发生了变化，但是这两个服务的方法实现和逻辑是完全相同的。

我想知道是否有一种方法可以将这两个服务合并为一个服务，或者创建一个父类，我可以仅使用变量类型进行扩展，但是所有名称和逻辑都将保持不变。

谢谢

Answer 1

一种方法是使用generic class，在其中您要为以后要指定的每种类型使用类型参数：

class GeneralThing<S, G, T> {
    synchronized: Map<string, Map<string, S>> = new Map();
    groupDispatchers: Map<string, Subject<G>> = new Map();
    subjectDispatchers: Map<string, Subject<T>> = new Map();

    public createNewSynchGroup(id?: string): Observable<G> {
        if (!id) throw new Error("What?!");

        this.synchronized.set(id, new Map());
        this.groupDispatchers.set(id, new Subject<G>());
        this.subjectDispatchers.set(id, new Subject<T>());

        return this.groupDispatchers.get(id)!.asObservable();
    }
}

在上文中，我将属性名称更改为通用名称（因此仅为synchronized和subjectDispatchers），并使用了类型参数S，G和T。

然后您可以将两个服务指定为

GeneralThing<MapSynchSettings, SynchMapGroupSubject, SynchMapSubject>

和

GeneralThing<SynchWaypointDrawerSettings, SynchWaypointDrawerGroupSubject, SynchWaypointSubject>

或者您可以给他们具体的名字，例如

class MapThing extends GeneralThing<
  MapSynchSettings, 
  SynchMapGroupSubject, 
  SynchMapSubject
> {}

class WaypointDrawerThing extends GeneralThing<
  SynchWaypointDrawerSettings, 
  SynchWaypointDrawerGroupSubject, 
  SynchWaypointSubject
> {}

希望有所帮助；祝你好运！

打字稿，同一个类，但属性类型不同？

1 个答案: