Question

我正在将numexpr模块用于python。我正在尝试运行下一个代码段：

<dependency>
    <groupId>com.querydsl</groupId>
    <artifactId>querydsl-apt</artifactId>
    <version>${com.querydsl.version}</version>
    <classifier>jpa</classifier>
</dependency>

但是import numexpr as ne def main(): result = ne.evaluate('where((1 > 9) & (where(1 > 9, 9, 1) == 0), 2, 3)') print(f'Result: {result}') if __name__ == "__main__": main()会引发以下错误：

numexpr

但是，如果我在单独的表达式中提取冲突的部分，那么它会起作用。

TypeError: unsupported operand type(s) for &: 'bool' and 'ConstantNode'

但是想法是有一个表达式。有谁知道我该如何重写此公式才能使其正常工作？

谢谢。

Answer 1

pop = (((0,4,0,4),10),((4,8,4,8),30))#original raster with two pixels, store as the Vertex coordinates ((xmin,xmax,ymin,ymax),pixel value) min_r_x = [] min_r_y = [] max_r_x = [] max_r_y = [] pop_r = [] x1 = [] x2 = [] y1 = [] y2 = [] #loc = [] pop_r = [] area = 4*4 #re = 4 newre = 2 #max_y = 4 #min_x = 0 val = [] #get the vertex coordinates of new raster for row in range(2): for col in range(4): min_r_x = 0 + col*newre max_r_x = 0 + (col+1)*newre max_r_y = 4 + row*(-newre) min_r_y = 4 + (row+1)*(-newre) pop_r.append(((min_r_x,max_r_x,max_r_y,min_r_y),0)) #take each of the new raster vertex cooordinates locate their position for i in range(len(pop_r)): pairs = pop_r[i] coor = pairs[0] #val = pairs[1] coorxmin = coor[0] coorxmax = coor[1] coorymax = coor[2] coorymin = coor[3]#loop each vertex of pixels for j in range(len(pop)): record = pop[j] loc = record[0] xmin = loc[0] xmax = loc[1] ymin = loc[2] ymax = loc[3] #here is the place that I have some problem, it seems not right if xmin <= coorxmin <= xmax: x1.append(xmax-coorxmin) val.append(record[1]) if xmin <= coorxmax <= xmax: x2.append(xmax - coorxmax) val.append(record[1]) if ymin <= coorymin <= ymax: y1.append(ymax-coorymin) val.append(record[1]) if ymin <= coorymax <= ymax: y2.append(ymax-coorymax) val.append(record[1]) value = (x1 * y1 * val + x1*y2*val + x2*y1*val + x2*y2*val)/area pop_r.append(((min_r_x[i],max_r_x[i],min_r_y[i],max_r_y[i]),value))是按位的&运算符。为什么不只使用and？

python numexp模块中带有“和”运算符的错误

1 个答案: