我正在尝试使用类Bone
创建一个类似“骨骼”的系统,并让“主要”骨骼的孩子由所有其他相连的骨骼组成。
public class Main {
public static void main(String[] args) {
Bone body = new Bone("primary", null);
Bone leftArm1 = new Bone("left_arm_1", body);
Bone leftArm2 = new Bone("left_arm_2", leftArm1);
Bone rightArm1 = new Bone("right_arm_1", body);
Bone rightArm2 = new Bone("right_arm_2", rightArm1);
List<Bone> bones = new ArrayList<Bone>();
for(Bone child : body.getChildren()) {
System.out.println(child.getName());
}
}
}
public class Bone {
private Bone parent = null;
private String name = null;
private List<Bone> children = new ArrayList<Bone>();
public Bone(String name, Bone parent) {
this.name = name;
this.parent = parent;
if(parent != null) {
parent.addChild(this);
}
}
public String getName() {
return this.name;
}
public Bone getParent() {
return this.parent;
}
public boolean hasParent() {
if(this.parent != null) {
return true;
} else {
return false;
}
}
public List<Bone> getChildren() {
return this.children;
}
public boolean hasChildren() {
if(this.children.isEmpty()) {
return false;
} else {
return true;
}
}
public void addChild(Bone child) {
this.children.add(child);
}
}
当前程序正在输出...
left_arm_1
right_arm_1
何时应该输出...
left_arm_1
left_arm_2
right_arm_1
right_arm_2
我如何使程序输出正确的字符串?
答案 0 :(得分:1)
我会使用递归
model = Sequential()
embedding_layer = Embedding(dictionary_size, num_word_dimensions,
weights=[embedding_weights], mask_zero=True,
embeddings_regularizer=regularizers.l2(0.0001))
model.add(TimeDistributed(embedding_layer,
input_shape=(max_conversation_length, timesteps)))
model.add(TimeDistributed(Bidirectional(LSTM(m // 2, return_sequences=True,
kernel_regularizer=regularizers.l2(0.0001)))))
model.add(TimeDistributed(Dropout(0.2)))
model.add(TimeDistributed(GlobalMaxPooling1D()))
model.add(Bidirectional(LSTM(h // 2, return_sequences = True,
kernel_regularizer=regularizers.l2(0.0001)),
merge_mode='concat'))
model.add(Dropout(0.2))
crf = CRF(num_tags, sparse_target=False, kernel_regularizer=regularizers.l2(0.0001))
model.add(crf)
model.compile(optimizer, loss = crf.loss_function, metrics=[crf.accuracy])
答案 1 :(得分:0)
由于body
只有2个孩子,因此输出仅为left_arm_1 right_arm_1
如果要打印所有子项,则需要递归地对所有子项进行打印,依此类推。