我有两个表,我想从第二个表中为第一个表中的每个记录选择随机值。问题在于,似乎该值对于每一行总是相同的,这意味着对于所有行仅执行一次。我该如何实现?
create table first_table(name varchar2(100));
insert into first_tablevalues('John');
insert into first_tablevalues('Jessie');
insert into first_tablevalues('Jack');
select * from second_table;
create table second_table(id number);
insert into second_table(id) values(1);
insert into second_table(id) values(2);
insert into second_table(id) values(3);
insert into second_table(id) values(4);
insert into second_table(id) values(5);
insert into second_table(id) values(6);
然后我执行了此查询,但是对于第一个表中的每个名称,我都会得到相同的数字。
SELECT NAME,
(SELECT id
FROM (SELECT id
FROM second_table
ORDER BY dbms_random.value)
WHERE rownum = 1)
FROM first_table;
答案 0 :(得分:4)
相关子句解决了这个问题:
SELECT NAME,
(SELECT id
FROM (SELECT id
FROM second_table st
ORDER BY dbms_random.value
)
WHERE rownum = 1 AND ft.name IS NOT NULL
)
FROM first_table ft;
Here是一个学期。
答案 1 :(得分:1)
这是丑陋的,但是-一种有效。
SQL> WITH ri
2 AS (SELECT s.id,
3 ROW_NUMBER () OVER (ORDER BY DBMS_RANDOM.VALUE) rn,
4 COUNT (*) OVER (ORDER BY NULL) cnt
5 FROM second_table s),
6 rn
7 AS (SELECT f.name,
8 ROW_NUMBER () OVER (ORDER BY DBMS_RANDOM.VALUE (1, ri.cnt))
9 rn
10 FROM first_table f JOIN ri ON 1 = 1)
11 SELECT rn.name, MAX (ri.id) id
12 FROM rn JOIN ri ON rn.rn = ri.rn
13 GROUP BY rn.name;
NAME ID
---------- ----------
Jack 3
John 2
Jessie 6
SQL> /
NAME ID
---------- ----------
John 5
Jack 6
Jessie 4
SQL> /
NAME ID
---------- ----------
Jack 6
John 2
Jessie 4
SQL> /
NAME ID
---------- ----------
Jack 5
John 6
Jessie 3
SQL> /
NAME ID
---------- ----------
John 6
Jack 3
Jessie 1
SQL>