R:new_quosures(NextMethod())中的错误:找不到函数“ new_quosures”

时间:2019-04-15 19:48:09

标签: r group-by dplyr quosure

考虑数据框:

data = data.frame(a=c(1,1,1,2,2,3),
              b=c("apples", "oranges", "apples", "apples", "apples", "grapefruit"),
              c=c(12, 22, 22, 45, 67, 28), 
              d=c("Monday", "Monday", "Monday", "Tuesday", "Wednesday", "Tuesday"),
              out = c(12, 14, 16, 18, 20, 22),
              rate = c(0.01, 0.02, 0.03, 0.04, 0.07, 0.06))

我正在尝试group_by并进行总结,但是,我不断收到错误消息

Error in new_quosures(NextMethod()) : 
  could not find function "new_quosures"

我正在使用的代码如下:

model.data.dim.names <-  c("a", "b", "c")

data2 <- data %>% group_by_(.dots = model.data.dim.names) %>% summarise(
    mean_adj1 = (mean(out, na.rm=FALSE)),
    mean_adj2 = (mean(out)/mean(rate))
  )

请注意,这是伪数据,并且在Windows操作系统中使用伪数据重现错误。此外,我正在Windows OS上工作。此外,我尝试了以下方法:

  1. 删除plyr
  2. 检查并编辑NA /无限值
  3. 将数据帧转换为数据表并运行代码

能否请您帮助我了解错误的根本原因或可以使用的替代方法?

Answer: 

1) tidyr library screws up with it. Removing tidyr helps
2) use most updated dplyr library and group_by/ group_by_at/group_by(!!!syms(model.data.dim.names) works

3 个答案:

答案 0 :(得分:1)

不推荐使用group-by_函数,当前的tidyeval方法是将字符向量转换为符号,然后取消引号将它们拼接为group_by

library(dplyr)

data %>%
  group_by(!!!syms(model.data.dim.names)) %>% 
  summarise(
    mean_adj1 = mean(out, na.rm=FALSE),
    mean_adj2 = mean(out) / mean(rate)
  )
## A tibble: 6 x 5
## Groups:   a, b [4]
#      a b              c mean_adj1 mean_adj2
#  <dbl> <fct>      <dbl>     <dbl>     <dbl>
#1     1 apples        12        12     1200 
#2     1 apples        22        16      533.
#3     1 oranges       22        14      700 
#4     2 apples        45        18      450 
#5     2 apples        67        20      286.
#6     3 grapefruit    28        22      367.

答案 1 :(得分:1)

我们可以使用group_by_at中的dplyr,它可以将字符串作为输入

library(dplyr)
data %>% 
   group_by_at(model.data.dim.names) %>% 
   summarise(
    mean_adj1 = mean(out, na.rm=FALSE),
    mean_adj2 = mean(out) / mean(rate)
  )
# A tibble: 6 x 5
# Groups:   a, b [4]
#      a b              c mean_adj1 mean_adj2
#  <dbl> <fct>      <dbl>     <dbl>     <dbl>
#1     1 apples        12        12     1200 
#2     1 apples        22        16      533.
#3     1 oranges       22        14      700 
#4     2 apples        45        18      450 
#5     2 apples        67        20      286.
#6     3 grapefruit    28        22      367.

答案 2 :(得分:1)

我在2周前的代码中也遇到了同样的错误。应用dplyr::group_by()时发生。我的dplyr软件包版本为0.7.6,并将其更新为0.8.0.1。这样就解决了问题。