当我尝试创建一个名称用空格分隔的文件夹时,它仅使用第一个单词,而忽略第二个单词。我该如何解决?我正在用php编写dovecot服务器。 LIST给出的空格是“ /”。
代码:
private const NEWLINE = "\r\n";
private socket = fsockopen("ssl://testmail.com", 465, $errno, $errstr,
20);
$foldername = "Hello World"
function createFolder($socket, $foldername) {
fputs($socket, "A3 Create " . $foldername . self::NEWLINE)
return read($socket);}
function read($socket)
{
stream_set_timeout($socket, 30);
$lines = [];
while(\FALSE !== ($line = fgets($socket))) {
$lines[] = $line;
if (\FALSE !== strpos($line, 'BAD')) {
break;
}
if (\FALSE !== strpos($line, 'NO')) {
break;
}
if (\FALSE !== strpos($line, 'OK')) {
break;
}
if (\FALSE === strpos($line, 'OK')) {
continue;
}
}
return $lines;}
我尝试了转义字符串并以另一种方式编写它,但是似乎没有任何效果。它确实创建了一个文件夹,但是如上所述,仅使用第一个单词。 服务器回复:
array(1) {[0]=>string(25) "A3 OK Create completed."}
edit:这是我尝试过的一些方法,一次是修改fputs,然后是在使用字符串时:
fputs($socket, "A3 Create " . \$foldername . self::NEWLINE) Result: HTTP ERROR 500
fputs($socket, "A3 Create " . '$foldername' . self::NEWLINE) Result: $foldername
fputs($socket, "A3 Create " . "$foldername" . self::NEWLINE) Result: Hello
fputs($socket, "A3 Create " . '\$foldername . self::NEWLINE) Result: \$foldername
fputs($socket, "A3 Create " . 'Hello' . 'World' . self::NEWLINE) Result: HelloWorld
fputs($socket, "A3 Create " . 'Hello ' . 'World' . self::NEWLINE) Result: Hello
fputs($socket, "A3 Create " . "Hello " . "World" . self::NEWLINE) Result: Hello
$foldername = "'Hello World'"; Result: 'Hello
$foldername = '"Hello World"'; Result: Hello
$foldername = 'Hello World'; Result: Hello
$foldername = "'Hello \ World'"; Result: 'Hello
$foldername = "<<<EOD Hello World EOD"; Result: <<<EOD
$foldername = '<<<EOD Hello World EOD'; Result: <<<EOD
$foldername = <<<EOD Hello World EOD; Result: Hello
$foldername = "%Hello World%"; Result: %Hello
$foldername = '%Hello World%'; Result: %Hello
$foldername = '\Hello World'; Result: \Hello
$foldername = "\Hello World"; Result: \Hello
答案 0 :(得分:1)
这有效:
$foldername = '"Hello\\ World"';
答案 1 :(得分:0)
将其括在引号中,以便发送:
A4 CREATE "Folder Name"
PHP不是我的语言,但是大概$foldername = '"Folder Name"'
之类的东西可以为您提供所需的信息。