我有一个数据集data = f(x,y)
。数据以网格格式提供。我想将其转换为数组,以使每一行都以[x,y,data]
格式排序。另外,该怎么做?
import numpy as np
x = np.arange(-5, 5, 0.1)
y = np.arange(-4, 4, 0.1)
xx, yy = np.meshgrid(x, y)
data = np.sin(xx**2 + yy**2) / (xx**2 + yy**2)
print(data) #Now it is in meshgrid format
答案 0 :(得分:0)
您可以使用以下方法重塑数据:
1。网格格式
import numpy as np
x = np.arange(-5, 5, 2)
y = np.arange(-4, 4, 2)
xx, yy = np.meshgrid(x, y)
data = np.sin(xx**2 + yy**2) / (xx**2 + yy**2)
print(data) # In meshgrid format
输出:
[[-0.00386885 -0.00529407 -0.05655279 -0.05655279 -0.00529407]
[-0.02288393 0.03232054 -0.19178485 -0.19178485 0.03232054]
[-0.00529407 0.04579094 0.84147098 0.84147098 0.04579094]
[-0.02288393 0.03232054 -0.19178485 -0.19178485 0.03232054]]
2。列格式:
z = len(x)*len(y)
a = np.reshape(xx, z)
b = np.reshape(yy, z)
c = np.reshape(data, z)
new = np.c_[a, b, c]
print(new) # In an array ordered like [x, y, data]
输出:
[[-5.00000000e+00 -4.00000000e+00 -3.86884558e-03]
[-3.00000000e+00 -4.00000000e+00 -5.29407000e-03]
[-1.00000000e+00 -4.00000000e+00 -5.65527936e-02]
[ 1.00000000e+00 -4.00000000e+00 -5.65527936e-02]
[ 3.00000000e+00 -4.00000000e+00 -5.29407000e-03]
[-5.00000000e+00 -2.00000000e+00 -2.28839270e-02]
[-3.00000000e+00 -2.00000000e+00 3.23205413e-02]
[-1.00000000e+00 -2.00000000e+00 -1.91784855e-01]
[ 1.00000000e+00 -2.00000000e+00 -1.91784855e-01]
[ 3.00000000e+00 -2.00000000e+00 3.23205413e-02]
[-5.00000000e+00 0.00000000e+00 -5.29407000e-03]
[-3.00000000e+00 0.00000000e+00 4.57909428e-02]
[-1.00000000e+00 0.00000000e+00 8.41470985e-01]
[ 1.00000000e+00 0.00000000e+00 8.41470985e-01]
[ 3.00000000e+00 0.00000000e+00 4.57909428e-02]
[-5.00000000e+00 2.00000000e+00 -2.28839270e-02]
[-3.00000000e+00 2.00000000e+00 3.23205413e-02]
[-1.00000000e+00 2.00000000e+00 -1.91784855e-01]
[ 1.00000000e+00 2.00000000e+00 -1.91784855e-01]
[ 3.00000000e+00 2.00000000e+00 3.23205413e-02]]
答案 1 :(得分:0)
您可以使用以下两个表达式:
# Convert from mesh to rows:
row_format = np.stack([z.ravel() for z in (xx, yy, data)], axis=1)
# Convert from rows to mesh:
xx, yy, data = np.swapaxes(row_format, 0, 1).reshape(3, len(y), len(x))