不能使用CLPlacemark快速获取subLocality

时间:2019-04-12 14:20:11

标签: swift swift3 clplacemark

我实际上正在迅速构建一个应用程序。 问题是应用程序应该从经度中获取子位置,并检查该子位置是否是数组的一部分,但是我无法获得子位置

这里的任何专业人士可以帮助我吗

这是所用的经度

let loc: CLLocation = CLLocation(latitude:43.60089111328125, longitude: 3.875329601741884)

ceo.reverseGeocodeLocation(loc, completionHandler: {(placemarks, error) in
                        if (error != nil)
                        {
                            print("reverse geodcode fail: \(error!.localizedDescription)")
                        }
                        let pm = placemarks! as [CLPlacemark]

                        if pm.count > 0 {
                            let pm = placemarks![0]
                            addressString = ""

                            if pm.name != nil {
                                addressString += pm.name! + ", "
                            }

                            if pm.isoCountryCode != nil {
                                addressString += pm.isoCountryCode! + ", "
                            }

                            if pm.country != nil {
                                addressString += pm.country! + ", "
                            }

                            if pm.postalCode != nil {
                                addressString += pm.postalCode! + ", "
                            }

                            if pm.administrativeArea != nil {
                                addressString += pm.administrativeArea! + ", "
                            }
                            if pm.subAdministrativeArea != nil {
                                addressString += pm.subAdministrativeArea! + ", "
                            }

                            if pm.locality != nil {
                                addressString += pm.locality! + ", "
                            }

                            if pm.subLocality != nil {
                                addressString += pm.subLocality! + ", "
                            }

                            if pm.thoroughfare != nil {
                                addressString += pm.thoroughfare! + ", "
                            }

                            if pm.subThoroughfare != nil {
                                addressString += pm.subThoroughfare! + ", "
                            }
                            if pm.areasOfInterest != nil {
                                print(pm.areasOfInterest!)
                            }

     print(pm.addressDictionary)
}
})

应该将GAMBETTA作为subLocality返回,但是什么也没发生。

2 个答案:

答案 0 :(得分:0)

您可以根据位置坐标使用Geocoder进行反向地理编码,这将返回CLPlacemark,然后可以检查subLocality是否存在,如下所示:

let geoCoder = CLGeocoder()
geoCoder.reverseGeocodeLocation(loc, completionHandler: { placemarks, error in
    // Place details
    guard let placeMark = placemarks?.first else { return }

    // SubLocality
    if let subLocality = placeMark.subLocality {
      // Do something if exists
    }
})

答案 1 :(得分:0)

可以请您尝试,它将为您提供帮助。

   let newlocation: CLLocation = CLLocation(latitude:43.60089111328125, longitude: 3.875329601741884)


        let geoCoder = CLGeocoder()
        geoCoder.reverseGeocodeLocation(newlocation, completionHandler: { (placemarks, error) -> Void in

            // Place details
            var placeMark: CLPlacemark!
            placeMark = placemarks?[0]

            print(placeMark.subLocality as Any)

            // Address dictionary
            print(placeMark.addressDictionary as Any)

            //City
            if let city = placeMark.addressDictionary!["City"] as? String {
                print("city : \(city)")
            }

     })