Question

我正在尝试一种编码方式，该方式仅允许该特定的javascript代码在小于900像素的屏幕尺寸上运行。此代码用于在移动设备上设置简单的左右导航按钮。但是，当我尝试使用matchMedia时，它会完全弄乱我的代码，但不会引发任何错误。您将如何处理这个问题？

   var flavorScroll = (function() {

        let widthMatch = window.matchMedia("(min-width: 901px)");


    if (widthMatch.matches) {
        var flavorBox1 = document.body.querySelector('#flavor-box-1');
        var flavorBox2 = document.body.querySelector('#flavor-box-2');
        var flavorBox3 = document.body.querySelector('#flavor-box-3');
        var flavorBox4 = document.body.querySelector('#flavor-box-4');

        var buttonRight = document.body.querySelector('#flavorButtonRight');
        var buttonLeft = document.body.querySelector('#flavorButtonLeft');

        var step = 1;

        leftButton.style.visibility = 'hidden';

        function flavorDisplayer(currentStep){
            if(currentStep === 1) {
                flavorBox1.style.display = 'block';

                flavorBox2.style.display = 'none';

                leftButton.style.visibility = 'hidden';
            } else if(currentStep === 2) {
                flavorBox2.style.display = 'block';

                flavorBox1.style.display = 'none';
                flavorBox3.style.display = 'none';

                leftButton.style.visibility = 'visible'; 
            } else if(currentStep === 3) {
                flavorBox3.style.display = 'block';

                flavorBox2.style.display = 'none';
                flavorBox4.style.display = 'none';

                rightButton.style.visibility = 'visible';
            } else if(currentStep === 4) {
                flavorBox4.style.display = 'block';

                flavorBox3.style.display = 'none';

                rightButton.style.visibility = 'hidden';
            }
        }





        buttonRight.addEventListener('click', function() {
            step += 1;

            flavorDisplayer(step);
        });

        buttonLeft.addEventListener('click', function() {
            step -= 1;

            flavorDisplayer(step);
        });

    } else {

        }

})();

Answer 1

这是我使用的便捷工具...

var breakpoint = {
  is(s) {
    const size = s.trim()
    const sizes = {
      xsmall: "480px",
      small: "576px",
      medium: "780px",
      large: "992px",
      xlarge: "1200px",
    }

    if (sizes.hasOwnProperty(size)) {
      // return mq(`only screen and (min-width: ${sizes[size]})`)
      return window.matchMedia(`only screen and (min-width: ${sizes[size]})`).matches
    }

    throw new ReferenceError(`The size ${size} is not a valid breakpoint: ${JSON.stringify(sizes)}`)
  },
}

然后，您可以将函数包装在if语句中，即

if (breakpoint.is("medium")) {
...
}

Answer 2

使用screen.width获取用户正在处理的屏幕的当前大小。然后使用该值限制执行代码的时间。

    var scrn = screen.width
    if (scrn < 2000) { console.log(1); };

仅在移动设备上使用某些JavaScript代码？

2 个答案: