Question

这是我的脚本的提示：询问用户“您确定吗？”的脚本

如果用户回答y或Y，则说“很高兴听到”，否则，如果用户输入n或N，则打印“对不起，您感觉不好”。如果用户输入其他字符，则打印错误的选择并再次询问问题。

这就是我所拥有的：

#! /bin/csh
echo "Are you OK? "
set n = $<
set loop = 1
if (("$n" == "y") || ("$n" == "Y")) then
    echo "glad to hear it"
else if (("$n" == "n") || ("$n" == "N")) then
    echo "sorry that you are not feeling good"
else
    echo "in-correct choice"
    while ( $loop == 1 )
      echo "Are you OK? "
      set n = $<
      if (("$n" == "y") || ("$n" == "Y")) then
        echo "glad to hear it"
        set loop = 0
      else if (("$n" == "n") || ("$n" == "N")) then
        echo "sorry that you are not feeling good"
        set loop = 0
      else
        echo "in-correct choice"
      endif
    end
endif

我一直收到错误消息“ else：endif not found”。同样，回声线“很高兴听到”，无论用户输入是否正确，每次都会运行。请帮忙。谢谢

Answer 1

只需在您的最后一个endif语句之后添加新行：

...
    end
endif
#new line

或者我建议始终以退出状态结束csh脚本，您应该可以进行以下操作：

...
    end
endif
exit (0)

无论如何，这里也很少重写您的脚本：

#!/bin/env csh
while (1)
  echo "Are you OK?"
  set n = "$<"
  if (("$n" == "y") || ("$n" == "Y")) then
    echo "glad to hear it"
    break
  else if (("$n" == "n") || ("$n" == "N")) then
    echo "sorry that you are not feeling good"
    break
  else
    echo "in-correct choice"
  endif
end
exit (0)

set n = $<这里的危险性更好set n = "$<"，以便不处理例如字符串y abc为是

继续收到“其他：找不到结尾”。错误

1 个答案: