Question

那我需要向用户请求3个项目，

向用户请求这三项物品的价格
计算所有三个总数
计算平均值
打印一条声明，“产品1，产品2，产品3的总和为xxxx，平均值为xxxx

我尝试使用6个字符串（因此3个用于产品，3个用于价格），所以我可以分别调用每个值。但是后来我被告知数组将极大地缩短代码并使代码整齐，所以我尝试了一下，但我一直在努力将其调用。我知道如何算出平均值和总数，但是我在数组部分上苦苦挣扎。

 products = []
 products = input("Please enter three shopping products: ")

然后打印代码，并允许我输入以下3种产品：请输入三种购物产品：洗发水，肥皂，面包（我仍然需要通过数组询问每种产品的价格）

shopping = products[0]
 print(shopping)
 S

我尝试的第一种方法是6个字符串，如下所示：

product1 = input("Please enter a shopping item: ")
product2 = input("Please enter a second shopping item: ")
product3 = input("Please enter a third shopping item: ")
price1 = input("Please enter the price for the first shopping item: ")
price2 = input("Please enter the price for the second shopping item: ")
price3 = input("Please enter the price for the third shopping item: ")

它打印问题并允许我输入，但看起来并不整洁。现在，我需要计算价格以及总数的平均值（我可以在没有数组的情况下执行此操作，但是如果使用数组，那会令人困惑）我希望我的最终结果是：

[product1]，[product2]，[product3]的总计为Rxx，xx，项目的平均价格为Rxx，xx。

Answer 1

products = []
prices = []
for i in range (0,3):
    product = raw_input("Enter your Item to the List: ")
    products.append(product)
for j in range (0,3):
    price = float(raw_input("Enter your price to the List: "))
    prices.append(price)
print "The total of products is " + str(sum(prices)) + " and the average price is " + str(sum(prices)/3)

Answer 2

您可以将输入拆分为一个数组，这将使代码缩短很多。

products = input("Please enter three shopping products (Seperated by comma): ")
result = [x.strip() for x in products.split(',')]

这会去除空格字符串，但会将它们分成一个数组。

Answer 3

itemsList = []
priceList = []


for i in range(1,4):
    itemStr = "Enter the {} shopping item: ".format(i)
    itemsList.append(input(itemStr))
    priceStr = "Enter the price of {} shopping item: ".format(itemsList[i-1])
    priceList.append(int(input(priceStr)))

print("The Total of {}, {}, {} is {} and the average price of the items are {}".format(*itemsList, sum(priceList), sum(priceList) / float(len(priceList))))

输出：

Enter the 1 shopping item: shopping_item_1
Enter the price of shopping_item_1: 1
Enter the 2 shopping item: shopping_item_2
Enter the price of shopping_item_2: 2
Enter the 3 shopping item: shopping_item_3
Enter the price of shopping_item_3: 3
The Total of shopping_item_1, shopping_item_2, shopping_item_3 is 6 and the average price of the items are 2.0

编辑：

如果购物商品是唯一的，我建议采用dict为items，keys为prices的{{1}}方法：

values

输出：

n = int(input("Enter the total items: "))
shoppingDict = {}

for i in range(n):
    keys = input("Enter the shopping item: ")
    values = int(input("Enter the price of item: "))
    shoppingDict[keys] = values

print("The Total of {}, {}, {} is {} and the average price of the items are {}".format(*shoppingDict.keys(), sum(shoppingDict.values()), sum(shoppingDict.values()) / float(sum(shoppingDict.values()))))

Answer 4

class ShoppingItem:
    price = 0
    name = ""

    def __init__(self, name, price):
        self.price = price
        self.name = name


shoppingItems = []

for i in range(0, 3):
    productName = input("Please enter a shopping item: ")
    price = input("Please enter a price for the shopping item: ")
    shoppingItems.append(ShoppingItem(productName, price))


total = sum(i.price for i in shoppingItems)
average = total/len(shoppingItems))

我如何使用数组来接受用户输入

4 个答案: