Question

这听起来可能令人困惑-我混淆了自己写的哈。所以基本上我有一些svg路径，它们都具有像20_11_3这样的id，它们是blockID_rowId_seatId。

<svg>
  <path class="seat" data-id="20_11_1"></path>
  <path class="seat" data-id="20_11_2"></path>
  <path class="seat is-available" data-id="20_11_3"></path>
  <path class="seat is-available" data-id="20_11_4"></path>
  <path class="seat" data-id="20_11_5"></path>
  <path class="seat" data-id="20_11_6"></path>
  <path class="seat is-available" data-id="20_11_7"></path>

  <path class="seat" data-id="20_12_1"></path>
  <path class="seat" data-id="20_12_2"></path>
  <path class="seat" data-id="20_12_3"></path>
  <path class="seat" data-id="20_12_4"></path>
  <path class="seat is-available" data-id="20_12_5"></path>
  <path class="seat" data-id="20_12_6"></path>
  <path class="seat" data-id="20_12_7"></path>

  <path class="seat" data-id="21_1_1"></path>
  <path class="seat" data-id="21_1_2"></path>
  <path class="seat is-available" data-id="21_1_3"></path>
  <path class="seat is-available" data-id="21_1_4"></path>
  <path class="seat is-available" data-id="21_1_5"></path>
  <path class="seat" data-id="21_1_6"></path>
  <path class="seat" data-id="21_1_7"></path>
</svg>

我需要抓住座位数最多的一组座位。因此，此选择上方的情况将是第21块第1行中三个可用座位的节点列表。

我想我必须首先使用querySelector all选择所有seat.is-available席位，然后对它们进行筛选以获取最多4个席位的最佳组。真的很努力地想出如何解决这个问题，而不会过度设计它。

希望这一切都有道理。

Answer 1

使用jQuery，您可以执行类似的操作。

// get first avalable seat
let $ele = $('.seat.is-available:eq(0)');
//  variable for holding largest range collection
let $maxRange;

// iterate until get empty
while ($ele.length) {
  // extract the id prefix
  let prefix = $ele.data('id').substr(0, $ele.data('id').lastIndexOf('_') + 1);

  // set current range as current element
  let $currentRange = $ele;
  // keep a temporary copy for  iterating
  let $tmp = $currentRange;
  // iterate until there is no adjacent availabe seat is there
  while (($tmp = $tmp.next(`[data-id^="${prefix}"].is-available`)).length)
    // add seat eleemnt to current range
    $currentRange = $currentRange.add($tmp);
  // check previous range and current range and update maxrange acconrdingly
  $maxRange = !$maxRange || $currentRange.length > $maxRange.length ? $currentRange : $maxRange;
  // get next available seat
  $ele = $currentRange.last().nextAll('.seat.is-available').first();
}


console.log($maxRange.map(function() { // extract seat ids
  return $(this).data('id');
}).get())

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<svg>
  <path class="seat" data-id="20_11_1"></path>
  <path class="seat" data-id="20_11_2"></path>
  <path class="seat is-available" data-id="20_11_3"></path>
  <path class="seat is-available" data-id="20_11_4"></path>
  <path class="seat" data-id="20_11_5"></path>
  <path class="seat" data-id="20_11_6"></path>
  <path class="seat is-available" data-id="20_11_7"></path>

  <path class="seat" data-id="20_12_1"></path>
  <path class="seat" data-id="20_12_2"></path>
  <path class="seat" data-id="20_12_3"></path>
  <path class="seat" data-id="20_12_4"></path>
  <path class="seat is-available" data-id="20_12_5"></path>
  <path class="seat" data-id="20_12_6"></path>
  <path class="seat" data-id="20_12_7"></path>

  <path class="seat" data-id="21_1_1"></path>
  <path class="seat" data-id="21_1_2"></path>
  <path class="seat is-available" data-id="21_1_3"></path>
  <path class="seat is-available" data-id="21_1_4"></path>
  <path class="seat is-available" data-id="21_1_5"></path>
  <path class="seat" data-id="21_1_6"></path>
  <path class="seat" data-id="21_1_7"></path>
</svg>

更新：根据您的要求，与id属性相同。

// get first avalable seat
let $ele = $('.seat.is-available:eq(0)');
//  variable for holding largest range collection
let $maxRange;

// iterate until get empty
while ($ele.length) {
  // extract the id prefix
  let prefix = $ele.attr('id').substr(0, $ele.attr('id').lastIndexOf('_') + 1);

  // set current range as current element
  let $currentRange = $ele;
  // keep a temporary copy for  iterating
  let $tmp = $currentRange;
  // iterate until there is no adjacent availabe seat is there
  while (($tmp = $tmp.next(`[id^="${prefix}"].is-available`)).length){
    // add seat eleemnt to current range
    $currentRange = $currentRange.add($tmp);
    }
  // check previous range and current range and update maxrange acconrdingly
  $maxRange = !$maxRange || $currentRange.length > $maxRange.length ? $currentRange : $maxRange;
  // get next available seat
  $ele = $currentRange.last().nextAll('.seat.is-available').first();
}


console.log($maxRange.map(function() { // extract seat ids
  return $(this).attr('id');
}).get())

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<svg>
  <path class="seat" id="20_11_1"></path>
  <path class="seat" id="20_11_2"></path>
  <path class="seat is-available" id="20_11_3"></path>
  <path class="seat is-available" id="20_11_4"></path>
  <path class="seat" id="20_11_5"></path>
  <path class="seat" id="20_11_6"></path>
  <path class="seat is-available" id="20_11_7"></path>

  <path class="seat" id="20_12_1"></path>
  <path class="seat" id="20_12_2"></path>
  <path class="seat" id="20_12_3"></path>
  <path class="seat" id="20_12_4"></path>
  <path class="seat is-available" id="20_12_5"></path>
  <path class="seat" id="20_12_6"></path>
  <path class="seat" id="20_12_7"></path>

  <path class="seat" id="21_1_1"></path>
  <path class="seat" id="21_1_2"></path>
  <path class="seat is-available" id="21_1_3"></path>
  <path class="seat is-available" id="21_1_4"></path>
  <path class="seat is-available" id="21_1_5"></path>
  <path class="seat" id="21_1_6"></path>
  <path class="seat" id="21_1_7"></path>
</svg>

根据ID选择多个元素以获得彼此相邻的最大组

1 个答案: