我的问题是,当我运行程序并删除所述目录中的文件时,当该文件(相同文件)放回原位时,它将返回不同的值。我想知道下面的代码是否有问题?
int main (int argc, char *argv[])
{
int fd;
int wd;
unsigned char c[SHA512_DIGEST_LENGTH];
int i;
SHA512_CTX mdContext;
int bytes;
unsigned char data[1024];
const int event_size = sizeof(struct inotify_event);
const int buf_len = 1024 * (event_size + FILENAME_MAX);
char *directory = "/home/joe/Documents/";
char *hashDirectory = "/home/joe/Documents/_Hash/";
char hashInBuf[500];
char hashOutBuf[500];
fd = inotify_init();
if (fd < 0) {
perror("inotify_init");
}
wd = inotify_add_watch(fd, "/home/joe/Documents", IN_CREATE);
while (1) {
char buff[buf_len];
int no_of_events, count = 0;
//SEARCH FOR NEW FILES WITHIN DIRECTORY
no_of_events = read (fd, buff, buf_len);
while (count < no_of_events) {
struct inotify_event *event = (struct inotify_event *)&buff[count];
if (event->len) {
if ((event->mask & IN_CREATE))
if(!(event->mask & IN_ISDIR)) {
snprintf(hashInBuf, sizeof(hashInBuf), "%s/%s", directory, event->name);
snprintf(hashOutBuf, sizeof(hashOutBuf), "%s/%s.txt", hashDirectory, event->name);
//OPEN FILES
FILE *ftest=fopen(hashInBuf, "rb"); //ORIGINAL FILE
FILE *ftest2=fopen(hashOutBuf, "wt"); //HASH FILE (stored in separate directory)
//HASH FUNCTION
SHA512_Init (&mdContext);
while ((bytes = fread (data, 1, 1024, ftest)) != 0)
SHA512_Update (&mdContext, data, bytes);
SHA512_Final (c,&mdContext);
for(i = 0; i < SHA512_DIGEST_LENGTH; i++){
fprintf(ftest2, "%02x", c[i]);
printf("%02x", c[i]);
}
fclose (ftest);
fclose (ftest2);
fflush (stdout);
}}
count += event_size + event->len;
}}
return 0;
} //CLOSES INT MAIN
我可以向您保证变量定义正确,因为它可以正常工作,只是不正确...
答案 0 :(得分:1)
您永远不会设置 hashInBuf 或 hashOutBuf ,所以其中的内容是未定义的,并且在您执行时
zsh
您尝试打开从未设置名称的文件,但是很遗憾,您没有检查打开失败的位置,所以
FILE *ftest=fopen(hashInBuf, "rb"); //ORIGINAL FILE FILE *ftest2=fopen(hashOutBuf, "wt"); //HASH FILE (stored in separate directory)
不读取任何内容,并且由于 ftest 的值为NULL,因此从未调用while ((bytes = fread (data, 1, 1024, ftest)) != 0)
等
从不使用几个变量: