Question

我正在根据喜欢的服务类型的排序列表对服务列表进行排序

我有sortingServices函数，该函数应该获取服务列表和喜欢的类型列表（来自用户对象），并且应该返回服务的排序对象列表。

class User :
    def __init__(self, id, rates):
        self.id = id
        self.rates = rates



user1 = User(123 , ["Education" , "food" , "shopping","A"])   

class Service :
    def __init__(self,id,body,type,fees):
        self.id = id
        self.body= body
        self.type=type 
        self.fee = fees


service1 = Service(123,"gh","food",12)
service2 = Service(123,"gh","Education",12)
service3 = Service(123,"gh","shopping",12)
service4 = Service(123,"gh","Education",12)
service5 = Service(123,"gh","Education",12)
service6 = Service(123,"gh","shopping",12)
service7 = Service(123,"gh","A",12)

Services= [service1,service2,service3,service3 ,service4,service5,service6,service7]


def sortingServices (services ,user):

   sorted(long_list, key=lambda e: (short_list.index(e),e) if e in short_list  else (len(short_list),e))

sortingServices(Services , user1)

输出应为：

Services = [service2 , service4 ,service5 , service1 , service3 , service6 , service7 ]

Answer 1

您需要检查Service.type是否在User.rates中并使用该索引。

例如：

Class User :
    def __init__(self, id, rates):
        self.id = id
        self.rates = rates      

user1 = User(123 , ["Education" , "food" , "shopping","A"])   

class Service :
    def __init__(self,id,body,type,fees):
        self.id = id
        self.body= body
        self.type=type 
        self.fee = fees    

service1 = Service(1,"gh","food",12)
service2 = Service(2,"gh","Education",12)
service3 = Service(3,"gh","shopping",12)
service4 = Service(4,"gh","Education",12)
service5 = Service(5,"gh","Education",12)
service6 = Service(6,"gh","shopping",12)
service7 = Service(7,"gh","A",12)

Services= [service1,service2,service3,service4,service5,service6,service7]

def sortingServices (long_list ,short_list):
    return sorted(long_list, key=lambda e: short_list.index(e.type) if e.type in short_list else len(short_list))

for i in sortingServices(Services , user1.rates):
    print(i.id)

输出：

根据另一个简短列表python对对象列表进行排序

1 个答案: