我试图运行一个while循环,当给定的输入不等于“ 1”,“ 2”或“ 3”时运行。
下面您将看到代码:
string get_menu_choice()
{
string option;
cout << "What action would you like to perform?" << endl;
cout << "1. View a room." << endl
<< "2. Create a new room." << endl
<< "3. Delete a room." << endl;
cout << "Enter your choice: ";
cin >> option;
while (option != "1" || option != "2" || option != "3")
{
cout << "Invalid input, enter in only 1, 2 or 3!" << endl;
cout << "Enter your choice: ";
cin >> option;
}
return option;
};
运行此命令时,它不接受1、2或3作为可接受的答案,并不断循环浏览
我尝试将语句更改为
while(options != ("1" || "2" || "3")){//code here}
,但这对我来说也不成功。
答案 0 :(得分:0)
您应编写如下代码:
while(option != "1" && option != "2" && option != "3")