Question

我有两个模型-

站：

class Station(db.Model):
    """Measurement station"""
    __tablename__ = "station"

    reference = db.Column(db.Text, nullable=False, primary_key=True)
    name = db.Column(db.Text, nullable=False, primary_key=True)
    status = db.Column(db.Text)


    river_analyses = db.relationship("RiverAnalysis")

和

RiverAnalysis：

class RiverAnalysis(db.Model):
    __tablename__ = "river_analysis"
    id = db.Column(db.Integer, nullable=False, primary_key=True)
    reference = db.Column(db.Text, db.ForeignKey("station.reference"), nullable=False)

    station_ref = db.relationship("Station", foreign_keys=reference)

当我尝试使用此迁移代码运行flask db upgrade

def upgrade():
    # ### commands auto generated by Alembic - please adjust! ###
    op.add_column('river_analysis', sa.Column('reference', sa.Text(), nullable=False))
    op.create_foreign_key(None, 'river_analysis', 'station', ['reference'], ['reference'])

我收到此错误：(psycopg2.ProgrammingError) there is no unique constraint matching given keys for referenced table "station"。

即使station.reference是Station的主键，我为什么也得到这个？

感谢您提供的任何帮助。

Answer 1

reference并不是您的主键，而是(reference, name)对。为了引用该密钥，您需要一个composite foreign key constraint：

class RiverAnalysis(db.Model):
    __tablename__ = "river_analysis"
    id = db.Column(db.Integer, nullable=False, primary_key=True)
    reference = db.Column(db.Text, nullable=False)
    name = db.Column(db.Text, nullable=False)

    __table_args__ = (
        db.ForeignKeyConstraint(
            [reference, name],
            ["station.reference", "station.name"]),
    )

为什么在引用主键时出现“非唯一”错误？

1 个答案: