这是我最终解决问题的方法：
我创建了两个列表，一个包含对象，另一个包含对象名称（字符串）。然后，我编写代码以确保将对象及其名称同时附加到两个列表中。这样我就可以轻松地使用ObjectList [NameList.index（Name）]调用对象，类似于使用NameList [ObjectList.index（Object）]来调用名称。
我不知道这是否是最好的解决方案。当我对python有更多了解时，也许我会找到一种更好的方法。
感谢大家的帮助。
我在下面更新了我的代码。
我正在尝试制作一款可以吸收用户输入，基于该输入制作新对象并将该对象与现有对象网络连接的游戏。
所以我有初始对象：Adam = Human("Male","God","God")和Eve = Human("Female", "God", "God")
但是在Adam和Eve之后，我想创建类似Josh = Human("Male", Adam, Eve)的对象，这里Josh的属性变成一个字符串和两个对象，而不是三个字符串。但是，如果这样做可行，我可以创建一个对象网络，其中每个对象孩子（亚当和夏娃除外）都有对象父母。
如果有人对此有任何建议，请告诉我。
我想传递用户输入的字符串作为某个类的新对象的名称。我不能使用eval()，因为这很危险。我该怎么办？
我是python3的新手，他创建了一个仅用于练习的小游戏。我创建了一个名为“人类”的类，在游戏中，用户应该输入一个新人类的名称。
我没有尝试太多，因为我发现的所有问题都不符合我的问题。我到目前为止只知道我不能使用eval()，因为如果发生eval("import")之类的事情，可能会引起麻烦。
import random
# list of all humans
Humans = []
# creating the class Human
class Human:
global Humans
def __init__(self, gender, father, mother):
self.gender = gender
self.father = father
self.mother = mother
self.canHaveChild = False
Humans.append(self)
def growup(self):
self.canHaveChild = True
Adam = Human("Male", "God", "God")
Eve = Human("Female", "God", "God")
Humans.append(Adam)
Humans.append(Eve)
# creating the class SpiritualHuman
class SpiritualHuman:
def __init__(self, gend, stparent, ndparent):
self.stparent = stparent
self.ndparent = ndparent
self.gend = gend
self.canHaveChild = False
# haveChild function
def haveChild(Human1, Human2):
gender = ""
gen_pro = random.random()
if gen_pro < 0.5:
gender = "Female"
else:
gender = "Male"
if Human1.canHaveChild & Human2.canHavechild:
if (Human1.gender == "Male") & (Human2.gender == "Female"):
return Human(gender, Human1, Human2)
elif (Human1.gender == "Female") & (Human2.gender == "Male"):
return Human(gender, Human1, Human2)
elif (Human1.gender == "Male") & (Human2.gender == "Male"):
return SpiritualHuman("Yang", Human1, Human2)
else:
return SpiritualHuman("Yin", Human1, Human2)
else:
return "forbidden child"
# a list of all commands
command_list = ["who is the mother of", "who is the father of", "who is the child of", "have child named"]
# user input could be:
# "who is the mother of xxx"
# "who is the father of xxx"
# "who is the child of xxx and xxx"
# "xxx and xxx have child named xxx"
# user input function
def get_input():
command = input(":")
comsplit = command.split()
# check 1st command
if command_list[0] in command:
if comsplit[5] in str(Humans):
print("the mother of", comsplit[5], "is", Humans[str(Humans).index(comsplit[5])].mother())
else:
print(comsplit[5], "does not exist")
# check 2nd command
elif command_list[1] in command:
if comsplit[5] in str(Humans):
print("the father of", comsplit[5], "is", Humans[str(Humans).index(comsplit[5])].father())
else:
print(comsplit[5], "does not exist")
# check 3rd command
elif command_list[2] in command:
if comsplit[5] in str(Humans) and comsplit[7] in str(Humans):
for i in Humans:
if str(i.father()) in [comsplit[5], comsplit[7]] and str(i.mother()) in [comsplit[5], comsplit[7]]:
print(i, "is the child of", comsplit[5], "and", comsplit[7])
else:
print("they don't have a child")
else:
print("at least one of the parents you mentioned does not exist")
# check 4th command
elif command_list[3] in command:
if comsplit[0] in str(Humans) and comsplit[2] in str(Humans):
# here's where the problem is
# I want to use comsplit[7] as name for a new Human object
# how should I do it?
else:
print("at least one of them is not human")
elif command == "humans":
print(str(Humans))
else:
print("invalid command. If you need help, please type 'help'")
while(True):
get_input()
我不知道如何避免错误，但是我希望用户输入以下内容：
Adam and Eve have child named Josh
结果应该是乔希是人类类的对象，其父亲是亚当，母亲是夏娃。
答案 0 :(得分：2)
使用包含您的人类的字典，将人类的名字作为键：
# global dict, defined at the top of your code
humans = {}
def get_input():
command = input(":").split()
if len(command) == 1:
print(HUMANS) # well, don't know what this one is supposed to be...
elif len(command) > 1:
humans[command[1]] = Human(command[1])
humans[command[2]] = Human(command[2])
humans[command[0]] = haveChild(humans[command[1]], humans[command[2]])
编辑：我刚刚阅读了您的评论，暂时无法完成回答，但是，简而言之，您必须先以人类的身份创建父母，然后才能使用它们，因此您需要以创建方式进行更改他们...
答案 1 :(得分：1)
用户将输入两个具有其属性（性别，父亲，母亲）的人类对象。这两个对象将传递给<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<meta name="viewport" content="width=device-width, initial-scale=1.0">
<meta http-equiv="X-UA-Compatible" content="ie=edge">
<title>Test</title>
<link rel="stylesheet" href="styles/grid.css">
<link rel="stylesheet" href="styles/normalize.css">
</head>
<body>
<main>
<div class="grid__container">
<div class="grid__item__1">
<img src="https://via.placeholder.com/600x150.png/b3dfbe">
</div>
<div class="grid__item__2">
<img src="https://via.placeholder.com/600x150.png/75c5b8">
</div>
<div class="grid__item__3">
<img src="https://via.placeholder.com/600x320.png/f16789">
</div>
<div class="grid__item__4">
<img src="https://via.placeholder.com/200x165.png/8d96f3">
</div>
<div class="grid__item__5">
<img src="https://via.placeholder.com/200x165.png/8d96f3">
</div>
<div class="grid__item__6">
<img src="https://via.placeholder.com/200x165.png/8d96f3">
</div>
<div class="grid__item__7">
<img src="https://via.placeholder.com/300x150.png/fac460">
</div>
<div class="grid__item__8">
<img src="https://via.placeholder.com/300x150.png/fac460">
</div>
<div class="grid__item__9">
<img src="https://via.placeholder.com/400x185.png/608cc9">
</div>
<div class="grid__item__10">
<img src="https://via.placeholder.com/400x185.png/608cc9">
</div>
<div class="grid__item__11">
<img src="https://via.placeholder.com/200x195.png/608cc9">
</div>
<div class="grid__item__12">
<img src="https://via.placeholder.com/200x195.png/608cc9">
</div>
<div class="grid__item__13">
<img src="https://via.placeholder.com/200x145.png/6653af">
</div>
<div class="grid__item__14">
<img src="https://via.placeholder.com/600x135.png/6653af">
</div>
<div class="grid__item__15">
<img src="https://via.placeholder.com/400x135.png/6653af">
</div>
</div>
</main>
</body>
</html>。检查我的代码
haveChild()