我在Rails 3应用程序中有Flight,Person和Glider模型。我已经定义了自定义关系,因为我需要多个外键引用来自flight表的Person。协会只能以单向工作。
class Flight < ActiveRecord::Base
belongs_to :pilot, :class_name => "Person"
belongs_to :instructor, :class_name => "Person"
belongs_to :towplane_pilot, :class_name => "Person"
belongs_to :airplane_instructor, :class_name => "Person"
belongs_to :glider
belongs_to :rep_glider, :class_name => "Glider"
belongs_to :departure_airfield, :class_name => "Airfield"
belongs_to :arrival_airfield, :class_name => "Airfield"
end
class Glider < Aircraft
has_many :flights
has_many :replaced_flights, :foreign_key => "rep_glider_id", :class_name => "Flight"
end
class Person < ActiveRecord::Base
has_many :flights, :foreign_key => "pilot_id", :class_name => "Flight"
has_many :instructed_flights, :foreign_key => "instructor_id", :class_name => "Flight"
has_many :towed_flights, :foreign_key => "towplane_pilot_id", :class_name => "Flight"
has_many :instructed_towing_flights, :foreign_key => "airplane_instructor_id", :class_name => "Flight"
end
####What works#####
Flight.first.glider
Flight.first.rep_glider
Flight.first.pilot
Flight.first.instructor
Flight.first.towplane_pilot
Flight.first.airplane_instructor
Glider.first.flights
Glider.first.replaced_flights
####What doesn't work#### ----> NoMEthodError 'match'
Person.first.flights
Person.first.instructed_flights
Person.first.towed_flights.
Person.first.instructed_towing_flights
我差不多了,但我不明白当Glider.first.flights
没有Person.first.flights
时class Airfield < ActiveRecord::Base
has_many :takeoff_flights, :foreign_key => "departure_airfield_id", :class_name => "Flight"
has_many :grounded_flights, :foreign_key => "arrival_airfield_id", :class_name => "Flight"
end
###Works Correctly
Airfield.first.takeoff_flights
Airfield.first.grounded_flights
Flight.first.departure_airfield
Flight.first.arrival_airfield
如何运作。
更新:与'机场'的关联工作...所以我对于为什么它不能与'人'合作
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答案 0 :(得分:0)
您的飞行员有类型吗?像pilot_type列一样?我也开始阅读这些模式,幸运的是它仍然有点新鲜(希望如果我是wron rails ninjas,请纠正我!))
您需要这里讨论的多态模式:
答案 1 :(得分:0)
我被告知这些模型之间的关联设置正确。
我在航班表中添加了一条新记录,现在这些协会可以正常使用这条新记录以及之前的所有记录。我现在不确定它是如何工作的,但确实如此。