Question

是否可以在同一行的HTML表的多个列中显示单个SQL列？

在此示例中，MySQL中的表具有一列（Col1）。我想将这些数据显示在单个ROW中，但要一列显示在三列中，所以我想将这些数据显示在三列下的三列中以显示最终结果，有没有办法做到这一点？

这是我的代码：

<?php
$con = new mysqli('domain', 'username', 'password', 'database');
$sql = "select * from table1";
$sql_query = mysqli_query($con, $sql);
echo "<table>";
echo "<tr>";
while ($row = mysqli_fetch_array($sql_query)) {
$col1 = $row['col1'];

echo "<td> $col1 </td>";
echo "<td> $col1 </td>";
echo "<td> $col1 </td>"; //The problem here that these data will repeat because we put the same variable in 3 TD and i want my data doesn't repeat.

}
echo "</tr>";
echo "</table>";
?>

Answer 1

那里：

<?php
    $con = new mysqli('domain', 'username', 'password', 'database');
    $sql = "select * from table1";
    $sql_query = mysqli_query($con, $sql);
    echo "<table>";
    echo "<tr>";
    $pos = 0;
    $results_per_row = 3; #you can change it to a different value
    while($row = mysqli_fetch_array($sql_query)){
        $pos++;
        $col1 = $row['col1'];
        echo "<td> $col1 </td>";
        if($pos % $results_per_row == 0) 
            echo "</tr><tr>";
    }
    // fill the last row with empty fields, if it has less than
    // $results_per_row values, to keep the proper table syntax
    while($pos % $results_per_row != 0){
        $pos++;
        echo "<td></td>";
    }
    echo "</tr>";
    echo "</table>";
?>

Answer 2

根据评论进行编辑：将表和tr标记移出循环。

<?php
    $con = new mysqli('domain', 'username', 'password', 'database');
    $sql = "select * from table1";
    $sql_query = mysqli_query($con, $sql);

    echo "<table><tr>";
    while ($row = mysqli_fetch_array($sql_query)) {
        $col1 = $row['col1'];
        echo "<td> $col1 </td>";
    }
    echo "</tr></table>";
?>

上一个回复

我不确定您要寻找的是什么，但我认为您担心的是重复多个表并输出一个值？

如果是这样，则应将循环表的开头和结尾的标记移到循环之外，然后对于每个单元格，回显该单元格所需的实际值。

<?php
    $con = new mysqli('domain', 'username', 'password', 'database');
    $sql = "select * from table1";
    $sql_query = mysqli_query($con, $sql);

    echo "<table>";
    echo "<tr><th>Col 1 Header Name</th><th>Col 2 Header Name</th><th>Col 3 Header Name</th></tr>";
    while ($row = mysqli_fetch_array($sql_query)) {

        echo "<tr>";
        echo "<td> $row['col1'] </td>";
        echo "<td> $row['col2'] </td>";
        echo "<td> $row['col3'] </td>"; 
        echo "</tr>";
    }
    echo "</table>";
?>

使用PHP

2 个答案: