有一个kml
文件的意图过滤器可以工作,但是我必须以内容方案的形式接收数据。
该文件是从File Commander中选取的。
数据
content://com.mobisystems.fileman.RemoteFiles/ZmlsZTovLy9zdG9yYWdlL2VtdWxhdGVkLzAvTG9jYXRpb24lMjBUcmFja2luZy8yMDE5LTA0LTA0JTIwMTclM0EyYy0
现在的问题是如何读取此文件? 我该如何解决这个问题? 任何帮助将不胜感激。
到目前为止,我已经尝试过
var uri = Uri.parse(trackString)
FileInputStream(contentResolver.openFileDescriptor(uri, "r").fileDescriptor)
contentResolver.openInputStream(uri) // not working
在manifest.xml
<!--Mime type set -->
<intent-filter>
<action android:name="android.intent.action.VIEW" />
<category android:name="android.intent.category.DEFAULT" />
<category android:name="android.intent.category.BROWSABLE" />
<data android:scheme="content" />
<!-- Valid mime types -->
<data android:mimeType="application/vnd.google-earth.kml+xml" />
<data android:mimeType="application/vnd.google-earth.kmz" />
<data android:mimeType="application/gpx+xml" />
<!-- Invalid mime types used by some bad software -->
<data android:mimeType="application/kml" />
<data android:mimeType="application/kmz" />
<data android:mimeType="application/gpx" />
<data android:mimeType="application/kml+xml" />
<data android:mimeType="application/kmz+xml" />
<data android:mimeType="application/vnd.google-earth.kml" />
<data android:mimeType="application/vnd.google-earth.gpx" />
<data android:mimeType="application/vnd.google-earth.kmz+xml" />
<data android:mimeType="application/vnd.google-earth.gpx+xml" />
<data android:mimeType="text/kml" />
<data android:mimeType="text/kmz" />
<data android:mimeType="text/gpx" />
<data android:mimeType="text/kml+xml" />
<data android:mimeType="text/kmz+xml" />
<data android:mimeType="text/gpx+xml" />
<data android:mimeType="text/xml+kml" />
<data android:mimeType="text/xml+kmz" />
<data android:mimeType="text/xml+gpx" />
</intent-filter>
<!-- Mime type not set but valid extensions -->
<intent-filter>
<action android:name="android.intent.action.VIEW" />
<category android:name="android.intent.category.DEFAULT" />
<category android:name="android.intent.category.BROWSABLE" />
<data android:scheme="content" />
<data android:host="*" />
<data android:pathPattern="/.*..*..*..*..*\\.gpx" />
<data android:pathPattern="/.*..*..*..*..*\\.kml" />
<data android:pathPattern="/.*..*..*..*..*\\.kmz" />
<data android:pathPattern="/.*..*..*..*\\.gpx" />
<data android:pathPattern="/.*..*..*..*\\.kml" />
<data android:pathPattern="/.*..*..*..*\\.kmz" />
<data android:pathPattern="/.*..*..*\\.gpx" />
<data android:pathPattern="/.*..*..*\\.kml" />
<data android:pathPattern="/.*..*..*\\.kmz" />
<data android:pathPattern="/.*..*\\.gpx" />
<data android:pathPattern="/.*..*\\.kml" />
<data android:pathPattern="/.*..*\\.kmz" />
<data android:pathPattern="/.*\\.gpx" />
<data android:pathPattern="/.*\\.kml" />
<data android:pathPattern="/.*\\.kmz" />
</intent-filter>
<!-- Invalid mime type but valid extensions -->
<intent-filter>
<action android:name="android.intent.action.VIEW" />
<category android:name="android.intent.category.DEFAULT" />
<category android:name="android.intent.category.BROWSABLE" />
<data android:scheme="content" />
<data android:host="*" />
<data android:mimeType="*/*" />
<data android:pathPattern="/.*..*..*..*..*\\.gpx" />
<data android:pathPattern="/.*..*..*..*..*\\.kml" />
<data android:pathPattern="/.*..*..*..*..*\\.kmz" />
<data android:pathPattern="/.*..*..*..*\\.gpx" />
<data android:pathPattern="/.*..*..*..*\\.kml" />
<data android:pathPattern="/.*..*..*..*\\.kmz" />
<data android:pathPattern="/.*..*..*\\.gpx" />
<data android:pathPattern="/.*..*..*\\.kml" />
<data android:pathPattern="/.*..*..*\\.kmz" />
<data android:pathPattern="/.*..*\\.gpx" />
<data android:pathPattern="/.*..*\\.kml" />
<data android:pathPattern="/.*..*\\.kmz" />
<data android:pathPattern="/.*\\.gpx" />
<data android:pathPattern="/.*\\.kml" />
<data android:pathPattern="/.*\\.kmz" />
</intent-filter>
更新
最后成功了,我通过uri.path
传递了uri
而不是intent
并出错了Uri.Parsing
,所以请继续检查该错误
contentResolver.openInputStream(uri) // works
答案 0 :(得分:1)
使用ContentResolver
和:
getType()
找出内容的MIME类型(因为您的<intent-filter>
支持许多类型)openInputStream()
以阅读内容通过在ContentResolver
上调用getContentResolver()
获得Context
。
答案 1 :(得分:0)
Cursor returnCursor = context.getContentResolver().query(yourFileUri, null, null, null, null);
int nameIndex = returnCursor.getColumnIndex(OpenableColumns.DISPLAY_NAME);
int sizeIndex = returnCursor.getColumnIndex(OpenableColumns.SIZE);
returnCursor.moveToFirst();
String name = (returnCursor.getString(nameIndex));
File file = new File(context.getCacheDir(), name);
try {
InputStream inputStream = context.getContentResolver().openInputStream(yourFileUri);
FileOutputStream outputStream = new FileOutputStream(file);
int read = 0;
int maxBufferSize = 1 * 1024 * 1024;
int bytesAvailable = inputStream.available();
int bufferSize = Math.min(bytesAvailable, maxBufferSize);
final byte[] buffers = new byte[bufferSize];
while ((read = inputStream.read(buffers)) != -1) {
outputStream.write(buffers, 0, read);
}
inputStream.close();
outputStream.close();
Log.d(TAG, "Path " + file.getPath());
Log.d(TAG, "Size " + file.length());
} catch (Exception e) {
Log.e("Exception", e.getMessage());
}
// To get the mime type of your file
public String getMimeType(Uri uri, Context ctx) {
String mimeType = null;
if (uri.getScheme().equals(ContentResolver.SCHEME_CONTENT)) {
ContentResolver cr = ctx.getContentResolver();
mimeType = cr.getType(uri);
} else {
String fileExtension = MimeTypeMap.getFileExtensionFromUrl(uri
.toString());
mimeType = MimeTypeMap.getSingleton().getMimeTypeFromExtension(
fileExtension.toLowerCase());
}
return mimeType;
}