Question

我正在使用列表来跟踪数字，并希望将列表索引与随机数匹配，因此我可以从该索引的值中减去1。

import random
race_length = int(input("Choose the Length You Would Like You Race To Be 
(Between 5 and 15)"))
dice = ["1", "2", "3", "4", "5", "6" ]
cars=[
    ["1", race_length],
    ["2", race_length],
    ["3", race_length],
    ["4", race_length],
    ["5", race_length],
    ["6", race_length],
]
while race_length >0:    
    print("Press Enter to Roll the Dice")
    input()
    chosen = int(random.choice(dice))
    print(int(chosen))

我该怎么办，这样我才能将所选的匹配项与列表中的数字进行匹配

Answer 1

无需与列表匹配，只需从列表中选择

import random
race_length = int(input("Choose the Length You Would Like You Race To Be (Between 5 and 15)"))
cars=[
    ["1", race_length],
    ["2", race_length],
    ["3", race_length],
    ["4", race_length],
    ["5", race_length],
    ["6", race_length],
]
while race_length >0:    
    print("Press Enter to Roll the Dice")
    input()
    chosen = random.choice(cars)
    print(chosen[0])
    chosen[1]-=1

您也将int方式转换为很多。因此print（int（“ 1”））会将“ 1”强制转换为1，然后又将其再次转换为“ 1”。

编辑：从选定项中减去一个可以简单地通过从索引1的选定字段中减去一个来完成。

Answer 2

...想要使列表索引与随机数匹配，所以我可以从该索引的值中减去1。

您不需要在cars中与每个元素一起添加索引。创建一个普通列表：

cars = [race_length] * len(dice)

索引并减去为：

cars[chosen-1] -= 1

代码：

import random

race_length = int(input("Choose the Length You Would Like You Race To Be (Between 5 and 15)"))
dice = ["1", "2", "3", "4", "5", "6" ]
cars = [race_length] * len(dice)
while race_length >0:    
    print("Press Enter to Roll the Dice")
    input()
    chosen = int(random.choice(dice))
    print(chosen)
    cars[chosen-1] -= 1
    print(cars)

但这将达到无穷大，用户必须终止自己的程序。

如何将随机数与列表中的数字匹配

2 个答案: